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Doss [256]
2 years ago
15

(0,5) and (-5,1) write a linear equation

Mathematics
2 answers:
tensa zangetsu [6.8K]2 years ago
5 0

Answer:

y=4/5x+5

Step-by-step explanation:

because this is the answer

pochemuha2 years ago
5 0

Answer: y = 2/5x + 5

Step-by-step explanation:

m = (1-5)/(-5-5)  = -4 / 10 = -4 / 10 divided by -2 = 2/5

(0,5) is the y-intercept B = 5

Therefore, y = 2/5x + 5

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melisa1 [442]

Given coordinates of the triangle RST are R(2,1), S(2,-2) and T(-1,-1).

Center of center of dilation is (2,-2).

Because center of dilation is (2,-2) so the coordinates of dilated image S(2,-2) would stay same.

Now, we need to apply rule for dilation with the scale factor 5/3.

Each of R(2,1), and T(-1,-1) would be and R' and T' would be in ratio 5/3.

We will extend RS to 5 units and TS also 5 units.

The new resulting image would be dilated triangle by a scale factor 5/3.

New coordinates would be

<h3>R'(2,3), S'(2,-2) and T'(-3,-2)</h3>

7 0
4 years ago
When i double my number and add eight i get my number plus twelve whats mynumber
ella [17]
(Put what the first number is) x (the previous number) + 8 + 12 = ?
5 0
3 years ago
A shoppers discount club charges a monthly fee of $15 and sells gasoline for $2.05 per gallon. The gas station across the street
svet-max [94.6K]
$15.75 dnnddbbd d d d Dbdjdhhdhdvdg
3 0
3 years ago
1. Find the quartiles for the tire pressures of car tires at an auto clinic. Tire pressure is measured in psi
marusya05 [52]

The quartiles and outliers for the data provided are as follows:

1. Quartiles for the tire pressures of car tires at an auto clinic:

  • Q2 = 28 psi
  • Q4 = 36 psi
  • Q1 = 21.5 psi
  • Q3 = 34 psi

2. The outlier(s) for the tires prices is $450

3. The outlier(s) for the tires prices is $650

4. The outlier(s) for the tires prices is $540

5. Quartiles for the tire pressures of car tires at an auto clinic are:

  • Q2 = 27 psi
  • Q4 = 35 psi
  • Q1 = 23.5 psi
  • Q3 = 33 psi

<h3>Quartiles</h3>

  • Quartiles are the values that divide a list of numbers into four parts or quarters after the numbers are arranged in ascending order.

They describe the dispersionof a set of data values.

  • Q1 is the first quartile or lower quartile. 25% of the numbers in the data set are at or below Q1.
  • Q2 is the second quartile. 50% of the numbers are below Q2, and
  • Q3 is the third quartile, or upper quartile. 75% of the numbers are at or below Q3.
  • Q4 is the maximum value in the data set. 100% of the numbers are at or below Q4.

<h3>Outliers</h3>

Outliers are data points that differs significantly from other observations.

There are two outliers: lower boundary outliers and upper boundary outliers.

  • Formula for lower boundary outliers is:

Q1 − 1.5(IQR)

  • Formula for upper boundary outliers is:

Q3 + 1.5(IQR)

where IQR is interquartile range

  • IQR = Q3 - Q1

<h3>1. Quartiles for the tire pressures of car tires at an auto clinic: (20, 27,19, 23, 29, 28, 34, 34, 36)</h3>

Arranging in increasing order:

19, 20, 23, 27, 28, 29, 34, 34, 36.

Q2 = 28

Q4 = 36

Q1 = (20 + 23) / 2

Q1 = 21.5

Q3 = (34 + 34) /2

Q3 = 34

<h3>2. Outlier(s) for these tires prices: $58, $95, $78, $125, $87, $158, $152, $182, $195, $450</h3>

Arranging in increasing order:

58, 78, 87, 95, 125, 152, 158, 182, 195, 450

Q1 = (87 + 78)/2

Q1 = 62.5

Q3 = 182 + 195/2

Q3 = 188.5

IQR = 188.5 - 62.5

IQR = 126

Lower boundary outlier(s) = 62.5 - 1.5(126)

Lower boundary outliers = -126.5

Thus there are no lower outliers.

Upper boundary outliers = 188.5 + 1.5(126)

Upper boundary outliers = 377.5

Therefore, 450 is an outlier.

<h3>3. The outlier(s) for these tires prices: $78, $195, $98, $145, $87, $138, $159, $172, $155, $210, $240, $650</h3>

Arranging in increasing order:

78, 87, 98, 138, 145, 155, 159, 172, 195, 210, 240, 650

Q1 = 98

Q3 = 210

IQR = 210 - 98

IQR = 112

Lower boundary outlier(s) = 98 - 1.5(168)

Lower boundary outliers = -70

Thus there are no lower outliers.

Upper boundary outliers = 210 + 1.5(112)

Upper boundary outliers = 378

Therefore, 650 is an outlier.

<h3>4. The outlier(s) for these tires prices: $88, $135, $75, $135, $85, $168, $156, $192, $195, $210, $230, $245, $540</h3>

Arranging in increasing order:

75, 85, 88, 135, 135, 156, 168, 192, 195, 210, 230, 245, 540

Q1 = (88 + 135)/2

Q1 = 111.5

Q3 = (210 + 230)/2

Q3 = 220

IQR = 220 - 111.5

IQR = 108.5

Lower boundary outlier(s) = 111.5 - 1.5(108.5)

Lower boundary outliers = - 51.25

Thus, there are no lower outliers.

Upper boundary outliers = 220 + 1.5(111.5)

Upper boundary outliers = 387.25

Therefore, 540 is an outlier.

<h3>5. Quartiles for the tire pressures of car tires at an auto clinic: 23, 29,18, 24, 27, 24, 35, 32, 34</h3>

Arranging in increasing order:

18, 23, 24, 24, 27, 29, 32, 34, 35.

Q2 = 27

Q4 = 35

Q1 = (23 + 24) / 2

Q1 = 23.5

Q3 = (32 + 34) /2

Q3 = 33

Learn more about quartiles and outliers at: brainly.com/question/24805469

4 0
3 years ago
Write in slope-intercept form an equation of the line that passes through the points (−15,−1) and (10,4).
grin007 [14]

Answer:

y =  \frac{1}{5} x + 2

Step-by-step explanation:

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept.

\boxed{slope =  \frac{y1 - y2}{x1 - x2} }

Slope

=  \frac{4 - ( - 1)}{10 - ( - 15)}

=  \frac{4 + 1}{10 + 15}

=  \frac{5}{25}

=  \frac{1}{5}

Substitute m= ⅕ into the equation:

y= ⅕x +c

To find the value of c, substitute a pair of coordinates.

When x= 10, y= 4,

4= ⅕(10) +c

4= 2 +c

c= 4 -2

c= 2

Thus, the equation of the line is y= ⅕x +2.

4 0
3 years ago
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