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Rudiy27
3 years ago
11

Can someone help me

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

m < 1 = 130°

m < 1 = 130°m < 2 = 50°

We know this is a linear pair, therefore the two angles must add up to 180°

(m < 1 )+ (m < 2 )= 180

5x + x + 24 = 180

Combine like terms

6x + 24 = 180

Isolate the variable

6x = 156

x = 26

Plug in 26 for x in both of the individual angle equations.

m < 1 = 5x

= 5(26)

= 130

m < 2 = x - 24

= (26) + 24

= 50

A good way to check if we did this correctly, is to add up the two angles. Because 180 + 50 = 180, we did this correctly.

I hope this helped. Let me know if you have any questions!

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Answer:

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Step-by-step explanation:

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}5x^3-8x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{5x^3}{x}=5x^2\\\mathrm{Quotient}=5x^2\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}5x^2:\:5x^3-15x^2\\\mathrm{Subtract\:}5x^3-15x^2\mathrm{\:from\:}5x^3-8x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=7x^2+9x+12\\\mathrm{Therefore}\\=5x^2+\frac{7x^2+9x+12}{x-3}

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}7x^2+9x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{7x^2}{x}=7x\\\mathrm{Quotient}=7x\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}7x:\:7x^2-21x\\\mathrm{Subtract\:}7x^2-21x\mathrm{\:from\:}7x^2+9x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=30x+12\\\mathrm{Therefore}\\=5x^2+7x+\frac{30x+12}{x-3}\\

\mathrm{Divide\:the\:leading\:coefficients\:of\:the\:numerator\:}30x+12\\\mathrm{and\:the\:divisor\:}x-3\mathrm{\::\:}\frac{30x}{x}=30\\\mathrm{Quotient}=30\\\mathrm{Multiply\:}x-3\mathrm{\:by\:}30:\:30x-90\\\mathrm{Subtract\:}30x-90\mathrm{\:from\:}30x+12\mathrm{\:to\:get\:new\:remainder}\\\mathrm{Remainder}=102\\\mathrm{Therefore}\\=5x^2+7x+30+\frac{102}{x-3}

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Read 2 more answers
he XO Group Inc. conducted a survey of brides and grooms married in the United States and found that the average cost of a weddi
ahrayia [7]

Answer:

A. P(X<20,000) = 0.0392

B. P(20,000 < x < 30,000) = 0.488

C. Amount = $39,070

Step-by-step explanation:

From XO group website

Cost of a wedding = $29,858

Mean, μ = $29,858

Standard Deviation, σ =$5,600

a. Calculating the probability that a wedding costs less than $20,000

P(X<20,000)?

First, the z value needs to be calculated.

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z = (20,000 - 29,858)/5600

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So, P(X<20,000) = P(Z<-1.76)

From the z table,

P(Z<-1.76) = 0.0392

P(X<20,000) = 0.0392

b. Calculating the probability that a wedding costs between $20,000 and $30,000

P(20,000 < x < 30,000)

First, the z value needs to be calculated.

z = (x - μ)/σ

When x = 20,000

z = (20,000 - 29,858)/5600

z = -1.76

When x = 30,000

z = (30,000 - 29,858)/5600

z = 0.02

P(20,000 < x < 30,000) = P(-1.76 < z <0.02) --- using the z table

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x = σz + μ

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Hence,

Option 2: \frac{4x-3y}{3x+4y} is the right answer

Keywords: fractions, simplification

Learn more about fractions at:

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