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olya-2409 [2.1K]
3 years ago
8

Question is the picture:

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0
I think that it is 3n + 1
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The mean consumption of water per household in a city was 1425 cubic feet per month. Due to a water shortage because of a drough
liberstina [14]

Answer:

a)t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

b) For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

Step-by-step explanation:

Information given

\bar X=1175 represent the sample mean for the cubic feets of households

\sigma=250 represent the population standard deviation

n=100 sample size  

\mu_o =1425 represent the value to verify

\alpha=0.025 represent the significance level

t would represent the statistic

p_v represent the p value

Part a

We want to test that the mean consumption of water per household has decreased due to the campaign by the city council, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1425  

Alternative hypothesis:\mu < 1425  

Since we don't know the deviation the statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

The statistic is given by:

t=\frac{1175-1425}{\frac{250}{\sqrt{100}}}=-10    

The degrees of freedom are given by:

df=n-1=100-1=99  

The p value for this case would be given by:

p_v =P(t_{99}  

Since the p value is significantly lower than he significance level given we have enough evidence to reject the null hypothesis and we can conclude that the true mean is lower than 1425

Part b

For this case we need to find a critical value in the t distribution with  99 degrees of freedom who accumulates 0.025 of the area in the right tail and we got:

t_{\alpha/2}=1.984

Since the calculated value is higher than the critical value we can reject the null hypothesis at the significance level provided and we can say that the true mean is higher than 1425

6 0
3 years ago
Helppppppppppppppppppppppppp
Wewaii [24]

Answer:

Radius: 8

Circumference: 50.27

πr^2 = Area of circle

201.06 = πr^2

divide by pi

201.06 / π = 63.9993857161 = 64

64 = r^2

Square root both sides to get radius.

\sqrt{64} = 8

r = 8

Circumference = π x diameter

Diameter = 2 x radius

Circumference = π x 16 = 50.2654824574 = 50.27

8 0
3 years ago
What is the reciprocal of 61
andre [41]

Answer:

1/61

Step-by-step explanation:

reciprocal just means you flip it. since 61 is a whole number. it would be 61/1 but you flip that over and its 1/61.

6 0
3 years ago
Read 2 more answers
W - 5,129 = 2,329<br><br>A. w = 7,468<br><br>B. w = 7,558<br><br>C. w = 7,458
Shkiper50 [21]
W−5129=2329

Step 1: Add 5129 to both sides.
(5129+2339)

w−5129+5129=2329+5129 =

w=7458

7 0
3 years ago
Which is the equation in the graph?
kompoz [17]

Answer:

D) y = 3x-2

Step-by-step explanation:

The y-intercept is (0,-2). This means that in y-mx+b, b is going to by -2. We know the slop is 3 because if I choose 2 points and move ONE unit to the right, it is increasing by 3. Also, you can do y1-y2/x1-x2, or y2-y1/x2-x1.

Please tell me if this is wrong and hope this helps :)

7 0
3 years ago
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