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liubo4ka [24]
3 years ago
10

Alguien me podría ayudar a resolver esto? Es urgente.

Mathematics
1 answer:
choli [55]3 years ago
4 0

Answer:

2x+y-3=0

Step-by-step explanation:

4x+2y-6=0

2x+y-3=0

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Margarita [4]

Answer:

b

Step-by-step explanation:

b

3 0
3 years ago
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Can somebody please solve question 11 for me?
love history [14]
1+tan^2(A) = sec^2(A) [Pythagorean Identities]

tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)


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6 0
4 years ago
If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
navik [9.2K]

Answer:

{1,2,3,7}

Step-by-step explanation:

The range of a relation is the set of y-values of the ordered pairs.

The given relation is:

ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)},

The set of y-values of the given ordered pairs are;

{1,2,3,7}

Therefore the range of y is {1,2,3,7}

5 0
3 years ago
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PLEASEEE HELP!!!!!!!!
Cloud [144]

Answer:

Number 2

Step-by-step explanation:

So you first gotta open the parentheses: When you multiply them you add the exponents

You get x^5/6 + 2x^7/3

8 0
3 years ago
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Find the value of y when x = 10, if y = 35 when x = 7.
olga55 [171]

Set up a proportion:

y = 35 when x = 7

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To get x from 7 to 10, you have to multiply by \frac{10}{7}. Therefore, you do the same to 35, and you get:

35 \times \frac{10}{7} = 50

And your answer is 50 :)

8 0
3 years ago
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