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marin [14]
3 years ago
5

These diagrams represent:

Mathematics
1 answer:
Oksana_A [137]3 years ago
8 0
4.) Angle Side Angle (ASA) congruence
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Given no other restrictions, what are the domain and range of the following funtction? f(x)=x^2-2x+2
STALIN [3.7K]

Answer: Domain of the given function is all real numbers.

Range of the given function is {y | y>=1}

Step-by-step explanation:

The given function is a polynomial and the domain of any polynomial is all the real numbers because for any value of x, the function will have some value.

Hence, the domain will be all real numbers.

Range is the set of y values for which the function is defined.

This is a polynomial and to find the range, we will simplify the polynomial.

f(x)=x^2-2x+2\\f(x)=(x-1)^2+1

Therefore, for any value of x, f(x) ≥ 1

Hence, the range becomes {y | y ≥ 1}

8 0
3 years ago
Read 2 more answers
Nicole used 3/8 of her ribbon to wrap a present. If she used 6 feet of ribbon for the present, how much ribbon did Nicole have a
Orlov [11]

<u>Your answer is 8 feet.</u>

--

Here are the steps:

Let the length of the ribbon be x.

Take 6x over 8 (6x/8) which equals 6.

Then, take 3x/4 which also will be 6 in this case.

3x = 24

x = 24 over 3 (24/3)

x = 8.

- -

Hope this helped :)

8 0
3 years ago
What is the relation between the trigonometric ratios tan(R) and tan(J)? Please answer ASAP!
Ilya [14]

Step-by-step explanation:

∆PQR similar to ∆ JKL

JK/KL= PQ/QR

6/12=3/QR

QR=3×2= 6

therefore, tan(R) = PQ/QR = 3/6=1/2

and, tan(J) = KL/JK =12/6=2

\frac{ \tan(R) }{ \tan(J) }  =  \frac{ \frac{1}{2} }{2}

\frac{ \tan(R) }{ \tan(J) }   =  \frac{1}{4}

tan(J)=4.tan(R)

option D

6 0
3 years ago
Suppose you take $5800 and invest it with an 8% interest rate for 16 years compounded continuously, how much money will you have
VladimirAG [237]

Answer:

$20,860.51

Step-by-step explanation:

The multiplier of the investment is e^(rt), where r is the interest rate and t is the time period. In this case, the balance will be ...

A = 5800·e^(0.08·16) = 5800·e^1.28 ≈ 5800·3.5966397 = 20,860.51

You will have about $20,860.51.

3 0
3 years ago
Three different divers kept track of the number of treasure boxes they've found this year. Diver Dives Treasure boxes found Scub
jok3333 [9.3K]

Answer:

Wet Suit Willy found the most treasures per dive.

Step-by-step explanation:

Given:

Diver name         Number of dive    Number of boxes

Sam                                  11                        33

Wet Suit Willy                  18                        81

Deep Diving Dan            26                       104

Find:

Who found the most treasures per dive

Computation:

Sam's per dive collection = 33 / 11 = 3 boxes

Wet Suit Willy's per dive collection = 81 / 18 = 4.5 boxes

Deep Diving Dan's per dive collection = 104 / 26 = 4 boxes

Wet Suit Willy found the most treasures per dive.

7 0
4 years ago
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