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aleksley [76]
3 years ago
14

What is the relation between the trigonometric ratios tan(R) and tan(J)? Please answer ASAP!

Mathematics
1 answer:
Ilya [14]3 years ago
6 0

Step-by-step explanation:

∆PQR similar to ∆ JKL

JK/KL= PQ/QR

6/12=3/QR

QR=3×2= 6

therefore, tan(R) = PQ/QR = 3/6=1/2

and, tan(J) = KL/JK =12/6=2

\frac{ \tan(R) }{ \tan(J) }  =  \frac{ \frac{1}{2} }{2}

\frac{ \tan(R) }{ \tan(J) }   =  \frac{1}{4}

tan(J)=4.tan(R)

option D

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kondor19780726 [428]

Answer:

1/4

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2 years ago
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Answer:

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6 0
3 years ago
One number exceeds another by 26. the sum of the numbers is 58. what are the numbers
Gnom [1K]
First number = X

second number = x +26  ( exceeds means higher so add 26)

x + x+26 = 58

combine like terms:

2x + 26 = 58
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2x = 32

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5 0
3 years ago
What is the area of this polygon?
ra1l [238]
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)

Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9. 

Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27

Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45

Final Answer: 45 square units

note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
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