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aleksley [76]
3 years ago
14

What is the relation between the trigonometric ratios tan(R) and tan(J)? Please answer ASAP!

Mathematics
1 answer:
Ilya [14]3 years ago
6 0

Step-by-step explanation:

∆PQR similar to ∆ JKL

JK/KL= PQ/QR

6/12=3/QR

QR=3×2= 6

therefore, tan(R) = PQ/QR = 3/6=1/2

and, tan(J) = KL/JK =12/6=2

\frac{ \tan(R) }{ \tan(J) }  =  \frac{ \frac{1}{2} }{2}

\frac{ \tan(R) }{ \tan(J) }   =  \frac{1}{4}

tan(J)=4.tan(R)

option D

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