9514 1404 393
Answer:
Step-by-step explanation:
Let d represent the number of dimes. Then 40-d is the number of nickels. The value is ...
0.10d +0.05(40 -d) = 2.60
0.05d = 0.60 . . . . . subtract 2.00
d = 0.60/0.05 = 12 . . . . . the number of dimes
40 -d = 40 -12 = 28 . . . . .the number of nickels
__
There are 0 quarters. There are 28 nickels.
Plugging in the numbers 7x - 2y = 39 fitted and made sense
Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So




Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So




The numerical limits for a B grade is between 81 and 89.
Answer:
The number of wreaths Alaina sells is 9 .
Step-by-step explanation:
As given
Alaina is selling wreaths and poinsettias for her chorus fundraiser.
Wreaths cost $27 each poinsettia cost $20 each.
If she sold 15 poinsettias and made $543.
Let us assume that the number of wreaths Alaina sells = x
As the number of poinsettias Alaina sells = 15
Than the equation becomes
27x + 15 × 20 = 543
27x + 300 = 543
27x = 543 - 300
27x = 243

x = 9
Therefore the number of wreaths Alaina sells is 9 .