If -2 (s - 7) > 4s + 8
then -2s + 14 > 4s + 8
14 - 8 > 4s + 2s
6 > 6s
∴ <span>all real numbers s such that -2(s - 7) > 4s + 8 are s < 1</span>
Answer:
C, 82 cm
Step-by-step explanation:
If the area of a rectangle is it's length times it's width and for the problem, it's maximum area must be 40cm than 40x1 would offer the largest perimeter with the smallest area respectively totalling at 82 cm.
12
<h3>
Further explanation</h3>
<u>Given:</u>
In an auditorium,
of the students are fifth graders,
are fourth graders, and
of the remaining students are second graders.
There are 96 students in the auditorium.
<u>Question:</u>
How many second graders are there?
<u>The Process:</u>
The least common multiple (LCM) of 3 and 6 is 6.
Let us draw the diagram of all students.

of the students are fifth graders, or 1 of 6 units above, that is 
are fourth graders, or 2 of 6 units above, that is 
The remainder is 6 units - (1 unit + 2 units) = 3 units, that is
. Or, 96 - 16 - 32 = 48 students.
of the remaining students are second graders.
Let us count how many second graders are there.

Thus, there are 12 second-graders in the auditorium.
- - - - - - - - - -
Quick Steps




We crossed out 24 and 96.


<h3>
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Keywords: In an auditorium, 1/6 of the students, fifth graders, 1/3, fourth, 1/4, the remaining students, second, 96, how many, second graders