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elena-14-01-66 [18.8K]
2 years ago
5

stanley bought 108 feet of fencing to put around his backyard. The Backyard is a square. Write a equation to find the dimensions

of his backyard. Is the area big enough for a pool that is 800ft² explain
Mathematics
1 answer:
Vlad1618 [11]2 years ago
4 0

Answer:

Step-by-step explanation:

If he requires 4 sides (sometimes a building is used as a side) then 108 feet would require each side would be 108/4 = 27 feet in length

Area = 27^2 = 729 square feet. That's less than 800

The pool requires slight downsizing to fit in the back yard.

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   If    -2 (s - 7) > 4s + 8
then  -2s + 14 > 4s + 8
           14 - 8 > 4s + 2s
                  6 > 6s
         
∴ <span>all real numbers s such that -2(s - 7) > 4s + 8  are   s < 1</span>
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What is the largest perimeter possible for a rectangle with positive whole number dimensions and an area of 40 cm?
Vladimir79 [104]

Answer:

C, 82 cm

Step-by-step explanation:

If the area of a rectangle is it's length times it's width and for the problem, it's maximum area must be 40cm than 40x1 would offer the largest perimeter with the smallest area respectively totalling at 82 cm.

8 0
3 years ago
3. In an auditorium, 1/6 of the students are fifth graders, 1/3 are fourth graders, and 1/4 of the remaining students are second
Katen [24]

12

<h3>Further explanation</h3>

<u>Given:</u>

In an auditorium,

  • \frac{1}{6} of the students are fifth graders,
  • \frac{1}{3} are fourth graders, and
  • \frac{1}{4} of the remaining students are second graders.

There are 96 students in the auditorium.

<u>Question:</u>

How many second graders are there?

<u>The Process:</u>

The least common multiple (LCM) of 3 and 6 is 6.

Let us draw the diagram of all students.

96 \div 6 \ units = 16 \rightarrow \boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16}\boxed{16} = 96 \ students

  • \frac{1}{6} of the students are fifth graders, or 1 of 6 units above, that is \boxed{16} = 16 \ students
  • \frac{1}{3} = \frac{2}{6} are fourth graders, or 2 of 6 units above, that is \boxed{16}\boxed{16} = 32 \ students

The remainder is 6 units - (1 unit + 2 units) = 3 units, that is \boxed{16}\boxed{16}\boxed{16} = 48 \ students. Or, 96 - 16 - 32 = 48 students.

\frac{1}{4} of the remaining students are second graders.

Let us count how many second graders are there.

\boxed{ \ \frac{1}{4} \times 48 \ students = ? \ }

Thus, there are 12 second-graders in the auditorium.

- - - - - - - - - -

Quick Steps

\boxed{ \ \frac{1}{4} \times \bigg(1 - \frac{1}{6} - \frac{1}{3} \bigg) \times 96 = ? \ }

\boxed{ \ = \frac{1}{4} \times \bigg(\frac{6}{6} - \frac{1}{6} - \frac{2}{6} \bigg) \times 96 \ }

\boxed{ \ = \frac{1}{4} \times \frac{3}{6} \times 96 \ }

\boxed{ \ = \frac{3}{24} \times 96 \ }

We crossed out 24 and 96.

\boxed{ \ = 3 \times 4 \ }

\boxed{\boxed{ \ = 12 \ students \ }}

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Keywords: In an auditorium, 1/6 of the students, fifth graders, 1/3, fourth, 1/4, the remaining students, second, 96, how many, second graders

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