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3 years ago

Which of the following is equivalent to the expression

Mathematics

1 answer:

alisha [4.7K]3 years ago

6 0

Answer:

i Choice A

Step-by-step explanation:

i ^ 41

we use the rule of 4 for powers of i

if you get remainder of 0 = 1

if you get remainder of 1 = i

if you get remainder of 2= -1

if you get remainder of 1 = -i

41/4 = 10 remainder 1

so i^41 = i

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2 years ago

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3 years ago

What is the y-intercept for y+2= -3/4(x+4)

fiasKO [112]

The answer would be: -5

Heres how you solve it!

First, change the x into a 0 so it can be removed.

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Now with the GCF you can reduce the numbers with 4.

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3 years ago

Please someone answer this please

gladu [14]

Option C:

$\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Solution:

Given expression:

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

To find which expression is equivalent to the given expression.

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}$

Using exponent rule: $\frac{1}{a^m}=a^{-m}, \ \ \frac{1}{a^{-m}}=a^{m}$

$$=\frac{-18 a^{-2} b^{5}a^{4} b^{6}}{-12 }$

$$=\frac{-18 a^{-2} a^{4} b^{5} b^{6}}{-12 }$

Using exponent rule: ${a^m}\cdot{a^n}=a^{m+n}$

$$=\frac{-18 a^{(-2+4)} b^{(5+6)}}{-12 }$

$$=\frac{-18 a^{2} b^{11}}{-12 }$

Divide both numerator and denominator by the common factor –6.

$$=\frac{3 a^{2} b^{11}}{2 }$

$$\frac{-18 a^{-2} b^{5}}{-12 a^{-4} b^{-6}}=\frac{3 a^{2} b^{11}}{2 }$

Therefore, $\frac{3 a^{2} b^{11}}{2 }$ is equivalent to the given expression.

Hence Option C is the correct answer.

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