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2 years ago

Which of the following is equivalent to the expression

Mathematics

1 answer:

alisha [4.7K]2 years ago

6 0

Answer:

i Choice A

Step-by-step explanation:

i ^ 41

we use the rule of 4 for powers of i

if you get remainder of 0 = 1

if you get remainder of 1 = i

if you get remainder of 2= -1

if you get remainder of 1 = -i

41/4 = 10 remainder 1

so i^41 = i

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Consider this expression 5/6(1/2x+6)-3x<br> What is the value of the expression evaluated for x=12

just olya [345]

ANSWER

The correct answer is $-26$

EXPLANATION

The expression given to us is,

$\frac{5}{6}( \frac{1}{2}x+ 6)-3x$

We plug in $x=12$ . That means we substitute 12 wherever we see x to obtain,

$\frac{5}{6}( \frac{1}{2}\times 12+ 6)-3\times 12$

We simplify the parenthesis first to obtain,

$=\frac{5}{6}( 6+ 6)-36$

$=\frac{5}{6}( 12)-36$

$=5\times 2-36$

$=10-36$

$=-26$

Hence the expression evaluates to $=-26$

7 0

3 years ago

Read 2 more answers

Plss help is this linear or non-linear??

skad [1K]

Answer:

linear

Step-by-step explanation:

The line is straight, it's not like going in any other direction at all or anything

3 0

2 years ago

Read 2 more answers

Help me answer this pls

stira [4]

Answer:

x=5

Step-by-step explanation:

From this information we know that,

$5x - 6 = 3x + 4 \\ 5x - 3x = 4 + 6 \\ 2x = 10 \\ x = 5$

Hope it helps :)

6 0

2 years ago

Please help! What’s the mean of 13, 13, 10?

avanturin [10]

Answer:

For mean it's the average. You add all three numbers (13, 13 , 10), then you divide it by three since their are three numbers. Average would be 12.

Hope this helps (:

8 0

2 years ago

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st

Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by

$Z = \frac{X - \mu}{\sigma}$

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so $\mu = 0.5, \sigma = 0.05$ .