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GarryVolchara [31]
3 years ago
7

Susan has 45 hats in 20 cupboards.her friends borrowed some of the hats. ,nick borrowed 3 hats and Shelly borrowed 2. hats. if S

usan divided the remaining hats into the cupboards., how many hats would be in each cupboard?
Mathematics
2 answers:
astraxan [27]3 years ago
6 0
To solve this we will first see how many hats Susan has left when she lets her friends borrow the hats.

45 - 3 = 42
42 - 2 = 40

So, Susan has 40 hats left after her friends borrowed some. Now lets divide to see how many hats will go in 1 cupboard.

40 ÷ 20 = 2
2 hats in each cupboard.

CHECK OUR WORK:-

20 × 2 = 40.
We were RIGHT!!!


So, after Susan's friends borrow some of her hats she can put 2 hats in each cupboard. 

Hope I helped ya!! 
g100num [7]3 years ago
4 0
45 - 3 = 42 42 - 2 = 40 So, Susan has 40 hats left after her friends borrowed some.The we divide by 20 40 ÷ 20 = 2 So 2 hats in each cupboard.
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Divid 15 into two parts such that the sum of their reciprocal is 3/10
emmasim [6.3K]
Let x and y be the 2 parts of 15 ==> x + y=15 (given)

Reciprocal of x and y ==> 1/x +1/y ==> 1/x + 1/y = 3/10 (given)


Let's solve  1/x + 1/y = 3/10 . Common denominator = 10.x.y (reduce to same denominator)

 ==> (10y+10x)/10xy = 3xy/10xy ==> 10x+10y =3xy

But x+y = 15 , then 10x+10y =150 ==> 150=3xy and xy = 50

Now we have the sum S of the 2 parts that is S = 15 and 
their Product = xy =50
Let's use the quadratic equation for S and P==> X² -SX +P =0
Or X² - 15X + 50=0, Solve for X & you will find:
The 1st part of 15 is 10 & the 2nd part is 5
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3 years ago
Express each fraction as a percent. Round your answer to the nearest whole number. 76/125
BartSMP [9]

Answer:

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Step-by-step explanation:

Multiply the fraction by 100%.

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3 0
3 years ago
A company rents out 15 food booths and 22 game booths at the county fair. The fee for a food booth is $100 plus $9 per day. The
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Rzqust [24]

Answer:

The rate of the plane is 862 miles per hour

Step-by-step explanation:

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Speed = distance / time

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Let x = speed of the airplane

Let y = speed of the wind

While travelling against the wind,

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Subtracting equation 2 from equation 1,

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y = -190/-2

y = 95 miles per hour

x = 957 - y

x = 957 - 95

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