(3 + 2) - 3² = 5 - 9 = -4
Regards :)
<h3>Given</h3>
trapezoid PSTK with ∠P=90°, KS = 13, KP = 12, ST = 8
<h3>Find</h3>
the area of PSTK
<h3>Solution</h3>
It helps to draw a diagram.
∆ KPS is a right triangle with hypotenuse 13 and leg 12. Then the other leg (PS) is given by the Pythagorean theorem as
... KS² = PS² + KP²
... 13² = PS² + 12²
... PS = √(169 -144) = 5
This is the height of the trapezoid, which has bases 12 and 8. Then the area of the trapezoid is
... A = (1/2)(b1 +b2)h
... A = (1/2)(12 +8)·5
... A = 50
The area of trapezoid PSTK is 50 square units.
Answer:
I think it is 90 and 100
Step-by-step explanation:
I used this equation: x is the speed of the slower train
910 = (5x + 10) + 5x
The correct answer is A. -22,14
Answer:
Scroll down to see the graph using the link
Step-by-step explanation:
https://www.symbolab.com/solver/step-by-step/-6x%2B2y%3D-8