Question

Elli’s age in 10 years will be the same as Peggy’s age is now. Five years from now, Peggy’s age will be twice Elli’s age. What are their present ages?

Answer 1

E + 10 = P
(P + 5) = 2(E +5)

E = P -10

P + 5 = 2((P-10)+5)
P + 5 = 2P -20 + 10
P + 5 =2P - 10
-P = -15
P = 15

Answer 2

Answer:

Elli's present age is 5 years and Peggy's present age is 15 years.

Step-by-step explanation:

Let Elli's present age be x

After 10 years Elli's age = x+10

Since we are given that Elli’s age in 10 years will be the same as Peggy’s age is now.

So, Peggy's present age = x+10

After 5 years

Elli's age will be x +5

Peggy's age = x+10 +5= x+15

Now we are given that Five years from now, Peggy’s age will be twice Elli’s age.

So, $x+15=2(x+5)$

$x+15=2x+10$

$x=5$

So, Elli's present age = 5 years

Peggy's present age = x+10 =5+10 = 15 years

Thus Elli's present age is 5 years and Peggy's present age is 15 years.