<ADB = 90 degrees
hope it helps
1) slope = (y₂-y₁)/(x₂-x₁)
Let A and B be A(4,-6) and B(0,2) ;
m = [2-(-6)]/[0-4) = (2+6)/(-4) → m = -2
2) Midpoint = value of x of the midpoint = (x₁+x₂)/2
value of y of the midpoint = (y₁+y₂)/2
x(midpoint) = (4+0)/2 → x= 2
y(midpoint) = (-6+2)/2 → y= - 2, so Midpoint M(2,-2)
3) Slope of the perpendicular bisector to AB:
The slope of AB = m = -2
Any perpendicular to AB will have a slope m' so that m*m' = -1 (or in other term, the slope of one is inverse reciprocal of the second, then if m =-2, then m' = +1/2 ; Proof [ (-2)(1/2) = -1]
4) Note that the perpendicular bisector of AB passes through the midpoint of AB or M(2,-2). Moreover we know that the slope of the bisector is m'= 1/2
The equation of the linear function is :
y = m'x + b or y = (1/2)x + b. To calculate b, replace x and y by their respective values [in M(-2,2)]
2= (1/2).(-2) + b → 2 = -1 + b → and b= 3, hence the equation is:
y = (1/2)x + 3
Answer:
Lies in the shaded regions of both the top and bottom inequalities.
Step-by-step explanation:
The point of solution for BOTH systems of inequalities must work for both equations. Therefore, the point has to lie in both top and bottom shaded regions or it won't work for both, but just one.
A parabola in mathematics is basically plane curve which is mirror-symmetrical and is approximately U-shaped. A point and a line in a U shape.
Example below:
Rate * time = distance traveled
55 * 4 = 220 miles
