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il63 [147K]
2 years ago
15

Write each decimal as a fraction or mixed number in simplest form.

Mathematics
1 answer:
umka2103 [35]2 years ago
5 0
1. 35/100
2. 136/33
Hope it work
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I Have attached an image. Please help me asap
alekssr [168]

Answer:

do you have choices? if not x=

11

16

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Step-by-step explanation: thats the best o could do

7 0
2 years ago
Read 2 more answers
1. What are two numbers that multiply to make -24 and sum to make -5?
charle [14.2K]
1) -8 and 3
because -8+3= -5 and -8x3=24
2) -8 and -5
because -8-5=-13 and -8x-5=40
8 0
3 years ago
OMG PLS HELP ME!!!!!! I NEED THIS ASAP!!! 100 PTS!!!!!!!<br><br> (its in the pic)
Rainbow [258]

By algebra properties we find the following relationships between each pair of algebraic expressions:

  1. First equation: Case 4
  2. Second equation: Case 1
  3. Third equation: Case 2
  4. Fourth equation: Case 5
  5. Fifth equation: Case 3

<h3>How to determine pairs of equivalent equations</h3>

In this we must determine the equivalent algebraic expression related to given expressions, this can be done by applying algebra properties on equations from the second column until equivalent expression is found. Now we proceed to find for each case:

First equation

(7 - 2 · x) + (3 · x - 11)

(7 - 11) + (- 2 · x + 3 · x)

- 4 + (- 2 + 3) · x

- 4 + (1) · x

- 4 + (5 - 4) · x

- 4 - 4 · x + 5 · x

- 4 · (x + 1) + 5 · x → Case 4

Second equation

- 7 + 6 · x - 4 · x + 3

(6 · x - 4 · x) + (- 7 + 3)

(6 - 4) · x - 4

2 · x - 4

2 · (x - 2) → Case 1

Third equation

9 · x - 2 · (3 · x - 3)

9 · x - 6 · x + 6

3 · x + 6

(2 + 1) · x + (14 - 8)

[1 - (- 2)] · x + (14 - 8)

(x + 14) - (8 - 2 · x) → Case 2

Fourth equation

- 3 · x + 6 + 4 · x

x + 6

(5 - 4) · x + (7 - 1)

(7 + 5 · x) + (- 4 · x - 1) → Case 5

Fifth equation

- 2 · x + 9 + 5 · x  + 6

3 · x + 15

3 · (x + 5) → Case 3

To learn more on algebraic equations: brainly.com/question/24875240

#SPJ1

5 0
1 year ago
Three numbers are in the ratio 2 : 3 : 4. The sum of their cubes is 33957. Find the largest number
lina2011 [118]
We take each number as x = 2x 3x 4x 
(2x)³+(3x)³+(4x)³=33957
8x³+27x³+64x³=33957
99x³=33957
x³=33957÷99
 =∛343
x=7
2x=2×7=14
3x=3×7=21
4x=4×7=28
=the three numbers are 14,21,28
4 0
2 years ago
I don't know how to do this
vesna_86 [32]
He could have 30 dimes and 13 quartars
7 0
3 years ago
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