All categories

1 year ago

Who wants to solve a question.

Mathematics

1 answer:

vovikov84 [41]1 year ago

6 0

Answer:

Step-by-step explanation:

5(p-3)

the 3 lbs she uses are being subtracted and then is being multiplied per lb

You might be interested in

If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?

Kay [80]

(f – g)(x) = 0

16x-30 -(14x-6) =0

distribute

16x-30 -14x+6 = 0

combine like terms

2x-24=0

add 24 to each side

2x=24

divide by 2

x=12

Answer: x=12

6 0

2 years ago

There are five students of different ages. Their median age is 13 years A) what are two possibilities for the ages of the three

Levart [38]

A) the median is the middle measurement. Their ages could be 13, 14 and 15.
B) 2 students must be younger than 13
C) Like I said, the median is the middle measurement. If you have a list of numbers, you have to order them and take the middle number.

:) Have a nice day and maybe consider grading this answer brainliest? <3

6 0

2 years ago

Given that (x+y+z)(xy+xz+yz)=18 and that x^2(y+z)+y^2(x+z)+z^2(x+y)=6 for real numbers x, y, and z, what is the value of xyz?

worty [1.4K]

Answer:

Step-by-step explanation:

$(x+y+z)(xy+xz+yz)=18$ Equation 1

$x^2(y+z)+y^2(x+z)+z^2(x+y)=6$ Equation 2

What is the value of $xyz$ where each variable represents a real number?

Let's expand equation 1:

$(x+y+z)(xy+xz+yz)=18$

$x(xy)+x(xz)+x(yz)+y(xy)+y(xz)+y(yz)+z(xy)+z(xz)+z(yz)=18$

Simplify each term if can:

$x^2y+x^2z+xyz+y^2x+xyz+y^2z+xyz+z^2x+z^2y=18$

See if we can factor a little to get some of the left hand side of equation 2:

The first two terms have $x^2$ and if I factored $x^2$ from first two terms I would have $x^2(y+z)$ which is the first term of left hand side of equation 2.

So let's see what happens if we gather the terms together that have the same variable squared together.

$x^2y+x^2z+y^2x+y^2z+z^2y+z^2x+xyz+xyz+xyz=18$

Factor the variable squared terms out of each binomial pairing:

$x^2(y+z)+y^2(x+z)+z^2(y+x)+xyz+xyz+xyz=18$

Replace the sum of those first three terms with what it equals which is 6 from the equation 2:

$6+xyz+xyz+xyz=18$

Combine like terms:

$6+3xyz=18$

Subtract 6 on both sides:

$3xyz=12$

Divide both sides by 3:

$xyz=4$

4 0

2 years ago

Is it possible to draw a triangle with numbers 5,6,11

Tatiana [17]

Answer:

Step-by-step explanation:

Let's use the Pythagorean Theorem. For those of you that don't know, it is $a^2 + b^2 = c^2\\$ .

11 is the bigger side in this case, so our formula would go like this: $5^2 + 6^2 = 11^2\\$ .

We now calculate to see if this is true.

25 + 36 $\neq$ 121

Therefore, the answer is wrong.

8 0

2 years ago

Read 2 more answers

The domain of the function f(x) = 3x3 is {2, 5}. What is the function’s range?

Sholpan [36]

The domain is {2,5} which the set containing the numbers 2 and 5. I'm assuming that the function is f(x) = 3x3. So...

when x = 2, f(x) = 3*23 = 3*8 = 24.
when x = 5, f(x) = 3*53 = 3*125 = 375.

so this means the functions range is {24, 375}

hope this helped you out

6 0

2 years ago