Question

A collapsible plastic bag contains a glucose solution. The acceleration of gravity is 9.8 m/s2 . h Glucose solution If the average gauge pressure in the vein is 14800 Pa, what must be the minimum height of the bag in order to infuse glucose into the vein? Assume that the specific gravity of the solution is 1.03. Answer in units of m.

Answer 1

Answer:

The height of the bag is 1.466 m.

Explanation:

Given that,

Acceleration of gravity $g=9.8\ m/s^2$

Pressure = 14800 Pa

Specific gravity = 1.03

We need to calculate the density

Using formula of specific gravity

$\rho_{s}=\dfrac{\rho}{\rho_{w}}$

$rho=\rho_{s}\times{\rho_{w}}$

Where, $\rho$ = density of solution

$\rho_{w}$ = density of water

Put the value in to the formula

$\rho=1.03\times1000$

$\rho=1030\ kg/m^3$

We need to calculate the height

Using formula of pressure

$P=\rho gh$

$h=\dfrac{P}{\rho g}$

Where, P = pressure

g = acceleration due to gravity

h = height

Put the value into the formula

$h = \dfrac{14800}{1030\times9.8}$

$h=1.466\ m$

Hence, The height of the bag is 1.466 m.