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3 years ago

What is the value of sec theta in the triangle below

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

3 0

Answer:

The answer to your question is the third choice secФ = 41/40

Step-by-step explanation:

Data

Opposite side = 9

Adjacent side = 40

hypotenuse = 41

Process

To solve this problem use trigonometric functions. The secant is the trigonometric function that relates the hypotenuse and the adjacent side.

sec Ф = hypotenuse / adjacent side

hypotenuse = 41

adjacent side = 40

then,

secФ = 41/40

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493.582 nearest hundredth

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Answer:

493.582 nearest hundredth

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2 years ago

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devlian [24]

Answer: 26

Work: 90 - 64 = 26

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2 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

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The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

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$V=\frac{4}{3}\pi (12)^{3}$

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2 years ago

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ale4655 [162]

Answer:

(2,-3)

x=2 y=-3

Step-by-step explanation:

2x+y=1 y=1-2x

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3 years ago

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Evgen [1.6K]

Answer:

the solution to the system is (5,3)

Step-by-step explanation:

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the third statement is True

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2 years ago