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2 years ago

Given: F(x)=2x-1; g(x)=3x+2; h(x)=x^2 find h(x+a)-h(x)

Mathematics

2 answers:

umka21 [38]2 years ago

5 0

$h(x)=x^2\\\\h(x+a)=(x+a)^2=x^2+2ax+a^2\\\\h(x+a)-h(x)=(x^2+2ax+a^2)-(x^2)=2ax+a^2$

shusha [124]2 years ago

4 0

yes a^2+2ax is correct

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Anuta_ua [19.1K]

Answer:

Data set doesn't go to 17

Step-by-step explanation:

None of the numbers go to 17

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2 years ago

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What value of w is a solution to this equation?<br> w/2 = 6<br> w = 10 or w = 12

Monica [59]

W=12 would be the correct answer. I got this because if you divided 12 by 2, (12/2) you would get 6!

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3 years ago

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

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2 years ago

Examples: Which type of triangle is graphed? Classify by Side and Angle. Then find the perimeter of each

OverLord2011 [107]

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2 years ago

Rooms in a hotel are numbered from 1 to 19.

skelet666 [1.2K]

Answer:

a) 8/19 chance

b) 7/19 chance (I'm not 100% sure)

Step-by-step explanation:

A) since there are 8 prime numbers from 1-19 we can say that the probability is 8 over 19 or 8/19

4 0

2 years ago