The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
1 answer:
Answer:
<h2>n = 8</h2>
Step-by-step explanation:
Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d
a = first term of the sequence
n = number of terms
d = common difference.
Given the first element a = 2 and 22nd to be 14
T22 = a+(22-1)d = 14
a+21d = 14
Substtuting a = 2 into the equation to get d
2+21d = 14
21d = 12
d = 12/21
d = 4/7
The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;
Tn = 2+(n-1)4/7
Given Tn = 6
6 = 2+(n-1)4/7
6 = 2+4/7 n - 4/7
6-2+4/7 = 4/7 n
32/7=4/7 n
32 = 4n
n = 32/4
n = 8
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A. 2x+3x-6=10+4x
5x-6=10+4x
5x=16+4x
X=16
Answer:
D. 165
Step-by-step explanation:
if A+n=180
75+90+n=180
165+n=180
n=180-165
n=15
A+n=180
A+15=180
A=180-15
A=165 (D)
Answer:
-2s
Step-by-step explanation:
2s+(-4s)
2s-4s
-2s
Hope this helps ;) ❤❤❤
Steps
8x−7y=−5
Add 7y to both sides
8x−7y+7y=−5+7y
Simplify
8x=−5+7y
Divide both sides by 8
8x
8 =−
5
8 +
7y
8
Simplify
x=
−5+7y
8
Your answer will be letter b
