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omeli [17]
4 years ago
10

If 21^(2x)=9 then what is the value of 21^(-x)? Answer and solution please ;)

Mathematics
1 answer:
azamat4 years ago
5 0
21^{2x}=9\\
(21^x)^2=9\\
21^x=3\\
(21^x)^{-1}=3^{-1}\\
21^{-x}=\frac{1}{3}

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