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Alchen [17]
3 years ago
8

What is the slope of the line through (3, 2) and (-3 ,4)

Mathematics
2 answers:
alexira [117]3 years ago
5 0
Answer:
-2/3
use rise/run
Delicious77 [7]3 years ago
4 0

Answer:

Slope = -\frac{2}{3}

Step-by-step explanation:

Slope = \frac{rise}{run}

Slope = \frac{y2-y1}{x2-x1}

Slope = \frac{4-2}{-3-3}

Slope = -\frac{4}{6}

Slope = -\frac{2}{3}

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What is the answer and steps to -3(5-9v)=25+7v
kompoz [17]
-3(5-9v)=25+7v
-15+27v=25+7v
+15 +15
27v=40+7v
-7v -7v
-20v=40
divide 40 by -20
v=-2
4 0
3 years ago
Read 2 more answers
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
You bought a video game for $35. You got it on sale
never [62]

Answer:

Sorry I feel bad I don't kt the answer sorry hope you find the answer tho

Step-by-step explanation:

sorry

7 0
3 years ago
How long will it take the United States to travel 1 kilometer
Svetradugi [14.3K]
It would take (100 km/hr)= 0.01 hr or 36 seconds.
3 0
2 years ago
Apply the Pythagorean Theorem to find the distance between points A and B.
irinina [24]

Answer:          

  Properties of a right tangle can be created in  a Coordinate Plane

  Distance between two points A and B are shown as below

Step-by-step explanation:

Find distance between two point using Pythagorean Theorem.

Properties of right triangles and creating right triangle as a coordinate Plane.

Suppose two point are drawn in triangle containing value of  (-2 , 4 ) and (-2, -2)

then

In (-2 , 4 ) and (-2,-2)

taking y-values that is  4 and -2

find difference between them such as

    4-(-2) = 6

Distance is (-2,4) is 6 unit from (-2,-2)

We can also find unit length of A and B

Side A:   (-1, 2) and (3,2)

      3-(-2)  = 5

side A is 5 unit in length

Side B : (-2,2) and (-2,-1)

      2 - (-1) = 3

Side B is 3 unit in length

7 0
3 years ago
Read 2 more answers
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