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motikmotik
3 years ago
10

Copyright law protects: Select one: a. Ideas which have been communicated orally to at least two witnesses. b. Websites, compute

r programs, and video games. c. Titles, names, short phrases, slogans, symbols and design. d. All works prepared by an officer or employee of the federal government as part of that person’s official duties.
Computers and Technology
1 answer:
kari74 [83]3 years ago
7 0

Answer:

Titles, names, short phrases, slogans, symbols and design.

Explanation:

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Given a String variable response that has already been declared, write some code that repeatedly reads a value from standard inp
OverLord2011 [107]

Answer:

The following code is:

do     // set do while loop

{

response = stdin.next();    

}

while (response != "Y" || response != "y" || response != "N" || response != "n");

//  terminate do while loop

Explanation:

The following code starts with do while loop whose variables has already declared and then we assume the availability of the variable "stdin" which references the Scanner object and write some code to execute inside the do-while loop.

5 0
3 years ago
Select all the correct answers
ikadub [295]
Umm I think 3 and 1
5 0
3 years ago
Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.
Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is \mathbf{2^{20}} entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

  • 32-bit logical address
  • Page size = 4 KB = \mathbf{2^{12} \ bytes }
  • Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = \mathbf{2^{26} \ bytes}

Thus, the number of bits in the physical address is computed as:

= \mathbf{log_2 \{Physical-memory-size\}}

=\mathbf{log_2(2^{26})}}

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table \mathbf{= \dfrac{2^{32}}{2^{12}}}

\mathbf{=2^{20}} entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= \mathbf{2^{20}\times 4 \ bytes}

= 4 MB

b.

suppose that this system supports up to 2^30 bytes of physical memory.

  • The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

  • This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is \mathbf{2^{20}} entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

#SPJ1

4 0
2 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to do the following:
abruzzese [7]

Answer:

The corrected code is as follows:

import java.util.Scanner;

public class U2_L4_Activity_Two{

public static void main(String[] args){

Scanner scan = new Scanner(System.in);

String str1 = scan.nextLine();

String str2 = str1;

str1 = str1.toUpperCase();

System.out.println(str1);

System.out.println(str2);

}

}

Explanation:

This corrects the scanner object

Scanner scan = new Scanner(System.in);

This line is correct

String str1 = scan.nextLine();

This copies str1 to str2

String str2 = str1;

This converts str1 to upper case

str1 = str1.toUpperCase();

This prints str1

System.out.println(str1);

This prints str2

System.out.println(str2);

8 0
3 years ago
RDBMS stands for_________________
Aliun [14]
The term "RDBMS" stands for <span>relational database management system. 

I hope this helped! :)</span>
4 0
4 years ago
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