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4 years ago

Help me with this question

Mathematics

1 answer:

qaws [65]4 years ago

8 0

Answer:

Area = $2^{2}$

Step-by-step explanation:

A = $\frac{h*b}{2}$
h = 2 b = 2
A = $\frac{2*2}{2} =2^{2}$

You might be interested in

The difference of 15 and x is 12

gulaghasi [49]

Answer:

X is 3

Step-by-step explanation:

15-x=12

X=15-12

X=3

8 0

3 years ago

Cal is packing his suitcase to go on a trip. He wants to pack 4 pairs of pants chosen from the 8 pairs of pants in his closet an

11111nata11111 [884]

Answer:

8820 ways

Step-by-step explanation:

Given that :

Selecting 4 pairs of pant from 8 available and selecting 5 shirts from 9 available

Using combination :

4 pants from 8 = 8C4

5 shirts from 9 = 9C5

Recall:

nCr = n! / (n-r)! r!

8C4 * 9C5 = [8! /(8-4)!4!] * [9! /(9-5)!5!]

8C4 * 9C5 = (8! /4!4!) * (9! /4!5!)

8C4 * 9C5 = 70 * 126

8C4 * 9C5 = 8820 ways

4 0

3 years ago

Find the future value of $2,000 deposited into a retirement account, after 20 years, if the interest rate is 6%, compounded quar

natta225 [31]

Answer:

$ 6581.33 ( approx )

Step-by-step explanation:

Since, future value formula in compound interest is,

$A=P(1+\frac{r}{n})^{nt}$

Where,

P = Principal amount,

r = annual rate,

n = number of compounding periods in a year,

t = number of years,

Here, P = $ 2,000, r = 6% = 0.06, n = 4 ( 1 year = 4 quarters ),

t = 20 years,

Hence, the future value would be,

$A=2000(1+\frac{0.06}{4})^{80}$

$=2000(1+0.015)^{80}$

$=2000(1.015)^{80}$

$=\$ 6581.32557398$

$\approx \$ 6581.33$

5 0

3 years ago

Suppose that 15% of people dont show up for a flight, and suppose that their decisions are independent. how many tickets can you

geniusboy [140]

Answer: 157 tickets

Explanation:

The people not showing up for the flight can be treated as from Binomial distribution.

The binomial distribution B(n, p) is approximately close to the normal i.e. N(np, np(1 − p)) for large 'n' and for 'p' and neither too close to 0 nor 1 .

Now, Let us assume 'n' = n

and we are given

p=0.15

So now B(n,0.15n) follows Normal distribution

u=n

$\sigma^{2}$ = 0.15n

We have to calculate P(X<144) with 99% accuracy

P(X<144) = P(Z<z)

where;

z= $(144-\bar{X})\div \sigma$

z score for 99% is 2.33

i.e.

$(144-\bar{X})\div \sigma = (144-n)/\sqrt{np} = 2.33\\\ (144-n)^{2} = \ np*2.33^{2}\\\ 20736 +n^{2} - 288n = 0.15n*5.43\\\ n^{2} - 288.81n + 20736=0$

solving this we will get one root nearly equal to 157 and other root as 133

Hence the answer is 157.

8 0

3 years ago

Help me please I’m taking a test:(

mrs_skeptik [129]

Answer:

Sarah incorrectly multiplied 9 and 6. her estimate should be $63

7 0

3 years ago

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