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Delvig [45]
3 years ago
10

Marla swims twice a week. her equipment cost her $32.85 and she has a membership to the pool for $35 plus #3.50 per visit. she c

an walk to the pool, so transportation is free. how much will swimming cost her for the year?
Mathematics
1 answer:
evablogger [386]3 years ago
3 0
Around $634.85 per year

Because:

$32.85+$35(12 months)+$3.5(52 weeks in a year)= Total cost per year
                   $420                       $182

        $32.85 + $420 + $182 = $634.85 per year
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A population is estimated to have a standard deviation of 9. We want to estimate the population mean within 2, with a 99% level
cupoosta [38]

Answer:

The sample required is  n = 135

Step-by-step explanation:

From the question we are told that

     The  standard deviation is  \sigma = 9

      The margin of error is E =  2

     

Given that the confidence level is  99%  then the level of  significance is mathematically evaluated as

         \alpha =  100-99

        \alpha =  1 \%

        \alpha =  0.01

Next we will obtain the critical value  \frac{\alpha }{2} from the normal distribution table(reference  math dot armstrong dot edu) , the value is  

             Z_{\frac{\alpha }{2} } =  Z_{\frac{0.05 }{2} } =  2.58

The  sample size is mathematically represented as

          n = [ \frac{Z_{\frac{\alpha }{2} } *  \sigma }{E} ]^2

substituting values

           n = [ \frac{ 2.58 *  9 }{2} ]^2

            n = 135

3 0
3 years ago
A recipe calls for 2 1/5 cups of chopped tomatoes and 3 2/5 cups of diced turnips how many more cups of turnips did the recipe c
Zarrin [17]
The answer would be 1 1/5 more turnips. 
6 0
3 years ago
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Which of the following is equal to [(x^2y^3)^-2/(x^6y^3z)^2]^-3
lara [203]

Answer:

A,B,D

Step-by-step explanation:

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4 0
3 years ago
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Andru [333]

Answer:

7

Step-by-step explanation:

3 0
3 years ago
In a study of the accuracy of fast food​ drive-through orders, one restaurant had 36 orders that were not accurate among 324 ord
tia_tia [17]

Answer:

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to​ 10%.

Step-by-step explanation:

We want to use a 0.01 significance level to test the claim that the rate of inaccurate orders is equal to​ 10%.

We set up our hypothesis to get:

H_0:p=0.10------->null hypothesis

H_1:p\ne0.10------>alternate hypothesis

This means that: p_0=0.10

Also, we have that, one restaurant had 36 orders that were not accurate among 324 orders observed.

This implies that: \hat p=\frac{36}{324}=0.11

The test statistics is given by:

z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }

We substitute to obtain:

z=\frac{0.11-0.1}{\sqrt{\frac{0.1(1-0.1)}{324} } }

This simplifies to:

z=0.6

We need to calculate our p-value.

P(z>0.6)=0.2743

Since this is a two tailed test, we multiply the probability by:

The p-value is 2(0.2723)=0.5486

Since the significance level is less than the p-value, we fail to reject the null hypothesis.

We do not have sufficient evidence to reject the claim that ,the rate of inaccurate orders is equal to​ 10%.

3 0
3 years ago
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