Answer:
JK+KL=JL
Step-by-step explanation:
- (x-6) +(2x-8) =16
- x-6+2x-8=16
- x+2x=16+6+8
- 3x=30
- x=30/3
- x=10
- Now KL
- 2x-8
- 2x10-8
- 20-8
- =1<u>2</u><u>(</u><u>A</u><u>)</u><u> </u>
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Answer:
False
Step-by-step explanation:
Lets call the three prime divisors of n p, q, and r, being r the largest, we know:
Now, if
then
So:
Also, for every natural greater than one, we know:
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D)
so
![\sqrt[3]{n}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%3C%5Csqrt%7Bn%7D%20%3C%20r)
from which:
![\sqrt[3]{n} < r](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bn%7D%20%3C%20r)
So, we see, this means the preposition is false, we can find a particular counterexample:
q=2
p=3
p*q = 6
We need to choose a prime greater than 6
r=7
n= 2 * 3 *7 = 42
![\sqrt[3]{42} = 3.4760 < 7](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B42%7D%20%3D%203.4760%20%3C%207)
For the answer to the question above,
the Order the set of numbers from least to greatest: square root 64, 8 and 1 over 7, 8.14 repeating 14, 15 over 2
15 over 2, square root 64, 8 1 over 7, 8.14 repeating 14
I hope my answer helped you. Feel free to ask more questions
The answer is 4440. You can determine this by using your rules of divisibility. We know that is must end in a 0 or 5 to be divisible by 5 and that the sum of the digits must be divisible by 3 in order to divide by 3. One or two 4's together are not divisible by 3. Three 4's are, but it must end in 0 to be divisible by 5 as well.
