Answer:
The first term of the sequence is a = 4
The sum of the first 13 terms is -480
Step-by-step explanation:
Given that:
The third term is: a + 2d = - 8 --- (1)

![-230 = \dfrac{10}{2}[2a+ (10-1)d]](https://tex.z-dn.net/?f=-230%20%3D%20%5Cdfrac%7B10%7D%7B2%7D%5B2a%2B%20%2810-1%29d%5D)
![-230 =5[2a+ (9)d]](https://tex.z-dn.net/?f=-230%20%3D5%5B2a%2B%20%289%29d%5D)
-230 = 10a + 45d
10a + 45d = -230 ----(2)
From (1) and (2)
a + 2d = - 8
10a + 45d = -230
From (1), let a = -8 - 2d
Replace, the value of a in (1) to equation (2)
10(-8 -2d) + 45d = -230
-80 -20d +45d =-230
25d = -230 + 80
25d = -150
d = -150/25
d = -6
From equation (1);
a + 2(-6) = -8
a -12 = -8
a = -8 + 12
a = 4
Thus,the first term of the sequence a = 4

![S_n = \dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_n = \dfrac{13}{2}[2(4)+(13-1)*-6]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cdfrac%7B13%7D%7B2%7D%5B2%284%29%2B%2813-1%29%2A-6%5D)
![S_n =7.5 [8+(12)\times -6]](https://tex.z-dn.net/?f=S_n%20%3D7.5%20%5B8%2B%2812%29%5Ctimes%20-6%5D)
![S_n =7.5 [8-72]](https://tex.z-dn.net/?f=S_n%20%3D7.5%20%5B8-72%5D)
= -480
Answer:
9
Step-by-step explanation:
Answer:
The interquartile range is 10.
Step-by-step explanation:
(xu-xl)=10
The 3rd one because you have to get the y-intercept also which is -6