<span>3[4(23)-52+7(8+42)-16]</span>
<span>3 x (4 x 8 - 52
+ 7 x (8 + 42) - 16)</span>
<span>3 x (32 - 52
+ 7 x (8 + 42) - 16)</span>
<span>3 x (16 – 52
+ 7 x (8 + 42))</span>
<span>3 x (16 - 25 +
7 x (8 + 42))</span>
<span>3 x (-9 + 7 x
(8 + 42))</span>
3 x (-9 +7 x
(8 + 16))
3 x (-9 + 7 x
24)
3 x (-9 + 168)
3 x 159
477
Answer:
The length of DC in meters is
⇒ A
Step-by-step explanation:
In the circle O
∵ AB passing through O
∴ AB is a diameter
∵ D is on the circle
∴ ∠ADB is an inscribed angle subtended by arc AB
∵ Arc AB is half the circle
→ That means its measure is 180°
∴ m∠ADB =
× 180° = 90°
In ΔADB
∵ m∠ADB = 90°
∵ AD = 5 m
∵ BD = 12 m
→ By using Pythagorase Theorem
∵ (AB)² = (AD)² + (DB)²
∴ (AB)² = (5)² + (12)²
∴ (AB)² = 25 + 144 = 169
→ Take square root for both sides
∴ AB = 13 m
∵ ∠ADB is a right angle
∵ DC ⊥ AB
∴ DC × AB = AD × DB
→ Substitute the lengths of AB, AD, and DB
∵ DC × 13 = 5 × 12
∴ 13 DC = 60
→ Divide both sides by 13
∴ DC =
m
∴ The length of DC in meters is
Answer:
Q = (1, -5)
Step-by-step explanation:
Reflection over x-axis (x,y) → (x,-y)
B = (1,5)
Q = (1,-5)
Answer:25 percent
Step-by-step explanation:
ANSWER
The value of the expression is

EXPLANATION
Method 1: Rewrite as product of

The expression given to us is,

We use the fact that

to simplify the above expression.

This implies,

We substitute to obtain,


Method 2: Use indices to solve.

This implies that,

