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3 years ago

Given the function: f(x) = 2x2 - 3x + 8, find f(-2).

Mathematics

1 answer:

Vaselesa [24]3 years ago

5 0

Answer: 22

<u>Step-by-step explanation:</u>

f(x) = 2x² - 3x + 8

f(-2) = 2(-2)² - 3(-2) + 8

= 2(4) + 6 + 8

= 8 + 6 + 8

= 22

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Polygon C and polygon D are similar. The perimeter of polygon C is 192 inches, and the perimeter of polygon D is 48 inches. If o

Marianna [84]

Answer:

B. 2 in.

Step-by-step explanation:

First, put the two perimeters together to form a fraction.

192/48, which can simplify to 4/1

Now, following the order in which you put the perimeters (I used C/D,) set it equal to the sides.

$\frac{4}{1} = \frac{8}{x}$

Now, cross multiply. (multiply 1 and 8, 4 and x.)

$4x = 8$

Now, solve.

x=2 inches.

3 0

3 years ago

Jose bought 4.75 pounds of pecans at $5.80 per pound. how much did jose pay for the pecans

butalik [34]

Answer:

27.55

Step-by-step explanation:

4.75 times 5.80 is 27.55

Hope it helps!

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3 years ago

3×42 using partial products

Mars2501 [29]

Answer:

126

Step-by-step explanation:

Although I don't know what you mean by partial products here is a step by step.

42*3

120+6

126

3 0

3 years ago

In ΔTUV, the measure of ∠V=90°, the measure of ∠T=55°, and VT = 56 feet. Find the length of TU to the nearest tenth of a foot.

HACTEHA [7]

Answer:

97.6

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the equilibrium quantity and equilibrium price for the commodity whose supply and demand functions are given.

expeople1 [14]

Rewriting the two equations:

[Supply] $p = q^2+20$
[Demand] $p=-4q^2+10q+18600$

Equilibrium price is when
Supply = Demand
$q^2+20 = -4q^2+10q+18600$
$q^2+4q^2+20-10q-18600 = 0$
$5q^2-10q-18580=0$ ⇒ Simplifying the equation by dividing each term by 5

$q^2-2q-3716=0$

The simplified equation is in quadratic form.
There are three main methods for solving a quadratic equation: factorizing, completing the square, or quadratic formula.

Using the formula, we need the value of a, b, and c which is the constant of the quadratic equation.
$q_1= \frac{-b+ \sqrt{(b)^2-4ac)} }{2a}$ , and $q_2= \frac{-b- \sqrt{(b)^2-4ac)} }{2a}$

We have a = 1, b = -2, and c = -3716
Substituting these values into the formula we have
$q_1= \frac{-(-2)+ \sqrt{(-2)^2-4(1*-3716)} }{2} =61.97$
$q_2= \frac{-(-2)- \sqrt{(-2)^2-4(1*-3716)} }{2} =-59.97$

Since 'q' represents a quantity, we can't have negative values, so we choose the value of 'q' to be 61.97 ≈ 62 (rounded to the nearest whole number)

Answer: Equilibrium quantity = 62

4 0

3 years ago