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just olya [345]
2 years ago
12

A line is represented by the equation y = 3x - 6. Which is a coordinate of a

Mathematics
1 answer:
Furkat [3]2 years ago
6 0

Answer:

(2,0)

Step-by-step explanation:

Simply plug in the coordinates. y= 3x - 6, so in this case 0= 3(2) - 6 or 0=0, making the point on the line. If the equation is not true like when using (0,3) and getting 3= -6, then the point is not on the line.

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ololo11 [35]

Answer:

From the graph attached, we know that \angle 1 \cong \angle 5 by the corresponding angle theorem, this theorem is about all angles that derive form the intersection of one transversal line with a pair of parallels. Specifically, corresponding angles are those which are placed at the same side of the transversal, one interior to parallels, one exterior to parallels, like \angle 1 and \angle 5.

We also know that, by definition of linear pair postulate, \angle 3 and \angle 1 are linear pair. Linear pair postulate is a math concept that defines two angles that are adjacent and for a straight angle, which is equal to 180°.

They are supplementary by the definition of supplementary angles. This definition states that angles which sum 180° are supplementary, and we found that \angle 3 and \angle 1 together are 180°, because they are on a straight angle. That is, m \angle 3 + m \angle 1 = 180\°

If we substitute \angle 5 for \angle 1, we have m \angle 3 + m \angle 5 = 180\°, which means that \angle 3 and \angle 5 are also supplementary by definition.

4 0
3 years ago
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Zigmanuir [339]

Answer:

6 units

Step-by-step explanation:

They are on the same y-point and so you just have to count the spaces between them on the x-axis.

4 0
3 years ago
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Use the distributive property to rewrite the expression in factored form.<br> 15g−40
muminat

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What is 6 plus 6x-20 over x^2-×
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Simplify 2x+6=4x+-2 reorder the terms 6+2x=4x+-2
7 0
3 years ago
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yan [13]

Answer:

y=-\dfrac{1}{2}(x+4)^2-1

Step-by-step explanation:

Vertex form:  y=a(x-h)^2+k  

where:

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  • a is some constant

Given:

  • vertex = (-4, -1)
  • point on parabola = (-2, -3)

Substitute given values into the formula to find a:

\implies -3=a((-2)-(-4))^2+(-1)

\implies -3=a(2)^2-1

\implies -3=4a-1

\implies -2=4a

\implies a=-\dfrac{2}{4}=-\dfrac{1}{2}

Therefore, the equation of the parabola is:

y=-\dfrac{1}{2}(x+4)^2-1

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2 years ago
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