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Paul [167]
3 years ago
10

5x-9y-42=?(x+6)-9(y+?)

Mathematics
2 answers:
iren [92.7K]3 years ago
5 0

Answer:

5 8

Step-by-step explanation:

Coefficient of x should be 5 so first ? should be 5 let the second ? = z

5×6-9×z=-42

30+42=9z

z=8

Dmitry [639]3 years ago
5 0

Answer:

5x-9y-42=5(x+6)-9(y+8)

Step-by-step explanation:

given 5x-9y-42=5x-9y-72+30

                        =5x+30-9y-72

                        =5(x+6)-9(y+8)

                      hence 5x-9y-42=5(x+6)-9(y+8)

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Please help me on this, thank you
Mumz [18]

Answer:

the formula

Step-by-step explanation:

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5 0
2 years ago
My pigg y bank has only pennies and nicklels in it , and 2/7 of the coins are nickel If i remove 84 pennies then 1/3 of the reme
zubka84 [21]

Answer:

There are 105 pennies in the piggy bank.

There are 42 nickels in the piggy bank.

Step-by-step explanation:

there are:

p pennies in the piggy bank

n nickels in the piggy bank

Then we can define T, the total number of coins, as:

T = p + n

We know that 2/7 of the total number of coins are nickels.

This can be written as:

n = (2/7)*T = (2/7)*(n + p)

And if we remove 84 pennies, 1/3 of the remaining coins are pennies.

This can be written as:

p - 84 = (1/3)*(n + p - 84)

Then we have a system of two equations:

n = (2/7)*(n + p)

p - 84 = (1/3)*(n + p - 84)

Let's solve the system, to do it, we first need to isolate one of the variables in one of the equations.

We can isolate n in the first one, to get:

n = (2/7)*(n + p) = (2/7)*n + (2/7)*p

n - (2/7)*n = (2/7)*p

n*(5/7) = (2/7)*p

n = (7/5)*(2/7)*p = (2/5)*p

n = (2/5)*p

Now we can replace this in the other equation:

p - 84 = (1/3)*(n + p - 84)

p - 84 = (1/3)*( (2/5)*p + p - 84)

Let's solve this for p

p - 84 = (1/3)*( (7/5)*p - 84)

3*(p - 84) = (7/5)*p - 84

3p - 252 = (7/5)*p - 84

3*p - (7/5)*p = 252 - 84

(15/5)*p - (7/5)*p = 168

(8/5)*p = 168

p = (5/8)*168 = 105

There are 105 pennies in the piggy bank.

And we know that:

n = (2/5)*p = (2/5)*105 = 42

There are 42 nickels in the piggy bank.

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