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3 years ago

3/5 ( x - 10 ) = 18 - 4x - 1 . Which terms can be combined

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

8 0

Answer:

see below

Step-by-step explanation:

3/5 ( x - 10 ) = 18 - 4x - 1

Combine like terms

3/5(x-10) = 17 -4x

Distribute

3/5x - 6 = 17 -4x

Add 6 to each side

3/5x -6+6 = 17 -4x+6

3/5x = 23 -4x

Add 4x to each side

3/5x +4x =23

Get a common denominator

3/5x + 20/5x =23

23/5 x =23

Multiply each side by 5/23 to isolate x

23/5x *5/23 = 23 * 5/23

x = 5

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sergey [27]

Answer:

x=12

Step-by-step explanation:

The right side is a right triangle

The base is 1/2 of the bottom or 5

The height is x and the hypotenuse is 13

We can use the Pythagorean theorem

a^2 +b^2 = c^2

5^2 +x^2=13^2

25+x^2 = 169

Subtract 25 from each side

25-25+x^2 = 169-26

x^2 =144

Take the square root of each side

sqrt(x^2) = sqrt(144)

x= 12

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3 years ago

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Digiron [165]

Answer:

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Step-by-step explanation:

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2 years ago

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Liono4ka [1.6K]

Answer:

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<h2>step by step Explanation:</h2>

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3 years ago

Solve for x <br> x(6x+1)= 2

Montano1993 [528]

Answer:

x=1/2,-2/3

Step-by-step explanation:

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3 years ago

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Which expression is equivalent to StartRoot 128 x Superscript 8 Baseline y cubed z Superscript 9 Baseline EndRoot? Assume y grea

Nataly [62]

Answer:

Option C.

Step-by-step explanation:

The given expression is

$\sqrt{128x^8y^3z^9}$

It can be written as

$\sqrt{(64\cdot 2)\cdot x^8\cdot y^{2+1}\cdot z^{8+1}}$

$=\sqrt{8^2\cdot 2\cdot (x^4)^2\cdot y^{2}\cdot y\cdot (z^{4})^2\cdot z}$

$=\sqrt{(8x^4yz^4)^2\cdot 2yz}$

$=8x^4yz^4\sqrt{2yz}$

Therefore, the correct option is C.

6 0

3 years ago