Question

The quadrtic expression x^2-2x-35 can be factored into (x+5)(x-7). Which ordered pairs represent the zeros of this expressionś related quadratic functions

Answer 1

Answer:

The ordered pairs of $p(x) = x^{2}-2\cdot x -35$ are $(r_{1}, p(r_{1})) = (-5, 0)$ and $(r_{2},p(r_{2})) = (7,0)$, respectively.

Step-by-step explanation:

Let be $p(x)$ a quadratic expression whose two real zeros are real, a value of $x$ is a zero of the expression when $p(x) = 0$. The factored form of the expression is represented by $p(x) = (x-r_{1})\cdot (x-r_{2})$, where $r_{1}$ and $r_{2}$ are the zeroes of the polynomial.

If $p(x) = x^{2}-2\cdot x -35$, then the ordered pairs that represent the zeros are:

$(r_{1}, p(r_{1})) = (-5, 0)$ and $(r_{2},p(r_{2})) = (7,0)$