Answer:
45 ?
Step-by-step explanation:
Answer:
2.5 is closer
Step-by-step explanation:
Had this on a worksheet for math.
Answer:
Step-by-step explanation:
Using the exponential growth function for the U. S. population from 1970 through 2003:
A = 205.1e^0.011t
with the U.S. population being 205.1 million in 1970, when would the U. S. population reach 350 million?
A.
2028
B.
2048
C.
2018
D.
2038
We have the expression
A = 205.1e^0.011t
We are asked to find when would the U. S. population reach 350 million
A = 350
350 = 205.1e^0.011t
We divide both sides by 205.1
Divide both sides by 205.1
350/205.1 = 205.1e^0.011t/205.1
1.7064846416 = e^0.011t
We take the log of both sides
log 1.7064846416 = log e^0.011t
log 1.7064846416 = t log 0.011
t = log 1.7064846416/ log 0.011
t = 0.1185057826
To solve this we are going to use the exponential function:

where

is the final amount after

years

is the initial amount

is the decay or grow rate rate in decimal form

is the time in years
Expression A

Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate

, we are going to use the formula:

*100%

*100%

*100%

5%
We can conclude that expression A decays at a rate of 5% every three months.
Now, to find the initial value of the function, we are going to evaluate the function at






We can conclude that the initial value of expression A is 624.
Expression B

Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:

*100%

*100

*100%

*100%

12%
We can conclude that expression B grows at a rate of 12% every 4 months.
Just like before, to find the initial value of the expression, we are going to evaluate it at






The initial value of expression B is 725.
We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months.
- Expression A has an initial value of 624, while expression B has an initial value of 725.