The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
<h3>How to find the derivative of a quadratic equation by definition of derivative</h3>
In this question we have a quadratic function, in which we must make use of the definition of derivative to find the expression of its first derivative. Then, the procedure is shown below:
f(x) = x² - 5 Given
f' = [(x + h)² - 5 - x² + 5] / h Definition of derivative
(x² + 2 · x · h + h² - 5 - x² + 5) / h Perfect square trinomial
(2 · x · h + h²) / h Associative, commutative and modulative properties / Existence of additive inverse
2 · x + h Distributive, commutative and associative properties / Definition of division / Existence of multiplicative inverse
2 · x h = 0 / Result
The first derivative of the function f(x) = x² - 5 is equal to f'(x) = 2 · x.
To learn more on derivatives: brainly.com/question/25324584
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Answer: THAT IS RIGHT OK BYE MAN
Step-by-step explanation: OK BYE
Answer:
<h2>x³ + x² - 3x - 3</h2>
Step-by-step explanation:
I'm assuming g*f means g times f, so you want to multiply the two functions together.
(x² - 3)(x + 1) Since the product is 2 binomials, use FOIL
= x²(x) + x²(1) - 3(x) - 3(1)
which simplifies to
<h2>x³ + x² - 3x - 3</h2>
Um well lets see there is no question so the day that ends in y
