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4 years ago

ANSWER FAST PLEASE!!!! Which one is closer to 3? 2.5 2 1/5

Mathematics

1 answer:

olasank [31]4 years ago

3 0

Answer:

2.5 is closer

Step-by-step explanation:

Had this on a worksheet for math.

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Maria bought seven boxes a week later half of all her boxes were destroyed in a fire there are now only 22 boxes that with how m

hodyreva [135]

Maria started off with 44 boxes.

6 0

3 years ago

Factor the expression using GCF 8 - 22

N76 [4]

2 is the greatest common factor. Neither 4 nor 8 divides into 8-22 without a remainder.

Thus, 8 - 22 = 2(4 -11) (answer)

7 0

3 years ago

In a large school, it was found that 77% of students are taking a math class, 74% of student are taking an English class, and 70

Iteru [2.4K]

Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that $P(A) = 0.77$

74% of student are taking an English class

This means that $P(B) = 0.74$

70% of students are taking both

This means that $P(A \cap B) = 0.7$

Find the probability that a randomly selected student is taking a math class or an English class.

This is $P(A \cup B)$ , which is given by:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

$P(A \cup B) = 0.77 + 0.74 - 0.7 = 0.81$

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

Find the probability that a randomly selected student is taking neither a math class nor an English class.

This is

$1 - P(A \cup B) = 1 - 0.81 = 0.19$

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

6 0

3 years ago

**will award BRAINLIEST** If angle D is a right angle and lines PN, FG, and BD are parallel to each other, prove triangle SPN ~

vredina [299]

Uses the rule RHS right angle hypotenuse and side for both of them therefore triangle spn and spg are congruent

7 0

4 years ago

This is going to be tricky pls solve from i ready

shutvik [7]

Answer:

4/10 meters

Step-by-step explanation:

Original Length : 7/10 meters

Remaining Length after cut : 3/10 meters

amount cut off = original length - remaining length

= 7/10 - 3/10

= (7-3)/ 10

= 4/10

3 0

3 years ago

Read 2 more answers