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3 years ago

A race car can travel 2 laps In 10 minutes How long will it take the race car to complete 100 laps at that rate ?

Mathematics

2 answers:

34kurt3 years ago

5 0

Answer:

500 minutes

Step-by-step explanation:

Ok, so the first thing we want to do is figure out how long it takes to complete one lap.

So if it takes 10 minutes to travel 2 laps lets find out how many minutes for one.

It would be 5 minutes for one lap, if you divide 10 by 2 because of the 2 laps.

Next, you just multiply the 5 minutes by 100 laps:

This gives you 500 minutes.

Hope this helps :)

lianna [129]3 years ago

3 0

Answer:

It would take 16.6 hours.

Step-by-step explanation:

10 mins. x 100 laps = 1,000 mins.

1,000 mins / 60 mins. = 16.6 hours.

I might be wrong on math, so correct me if I am.

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11x + 6y = 6 then graph the equation

maw [93]

Answer:

Step-by-step explanation:

Use the intercept method of graphing a straight line:

Let x = 0. We get y = 1. This is the y-intercept (0, 1).

Let y = 0. We get x = 6/11. This is the x-intercept (6/11, 0).

Plot both points and then draw a straight line through them.

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3 years ago

a landscaping company delivers soul and bags to its customers they deliver 4,000 pounds of soil if each bag holds 16 pounds of s

Murljashka [212]

Answer:

250 bags

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Could someone help me please

Rina8888 [55]

Answer:

the answer should be 30

Step-by-step explanation:

since you can divided 15 by 5 to get 3, you can multiply 10 x 3 to get 30

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3 years ago

The price of a car increased by 7% which expression can be used to calculate the new price of the car

julsineya [31]

Answer: P * ( 1 + 7%)

Step-by-step explanation:

You included no options but the expression should go something like this:

Pn = P * ( 1 + 7%)

Where Pn is the new price

P is the current price

<em>The above formula will show the new price given the current price. </em>

6 0

3 years ago

I am having trouble with this relative minimum of this equation.<br>

Norma-Jean [14]

Answer:

So the approximate relative minimum is (0.4,-58.5).

Step-by-step explanation:

Ok this is a calculus approach. You have to let me know if you want this done another way.

Here are some rules I'm going to use:

$(f+g)'=f'+g'$ (Sum rule)

$(cf)'=c(f)'$ (Constant multiple rule)

$(x^n)'=nx^{n-1}$ (Power rule)

$(c)'=0$ (Constant rule)

$(x)'=1$ (Slope of y=x is 1)

$y=4x^3+13x^2-12x-56$

$y'=(4x^3+13x^2-12x-56)'$

$y'=(4x^3)'+(13x^2)'-(12x)'-(56)'$

$y'=4(x^3)'+13(x^2)'-12(x)'-0$

$y'=4(3x^2)+13(2x^1)-12(1)$

$y'=12x^2+26x-12$

Now we set y' equal to 0 and solve for the critical numbers.

$12x^2+26x-12=0$

Divide both sides by 2:

$6x^2+13x-6=0$

Compaer $6x^2+13x-6=0$ to $ax^2+bx+c=0$ to determine the values for $a=6,b=13,c=-6$ .

$a=6$

$b=13$

$c=-6$

We are going to use the quadratic formula to solve for our critical numbers, x.

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-13 \pm \sqrt{13^2-4(6)(-6)}}{2(6)}$

$x=\frac{-13 \pm \sqrt{169+144}}{12}$

$x=\frac{-13 \pm \sqrt{313}}{12}$

Let's separate the choices:

$x=\frac{-13+\sqrt{313}}{12} \text{ or } \frac{-13-\sqrt{313}}{12}$

Let's approximate both of these:

$x=0.3909838 \text{ or } -2.5576505$ .

This is a cubic function with leading coefficient 4 and 4 is positive so we know the left and right behavior of the function. The left hand side goes to negative infinity while the right hand side goes to positive infinity. So the maximum is going to occur at the earlier x while the minimum will occur at the later x.

The relative maximum is at approximately -2.5576505.

So the relative minimum is at approximate 0.3909838.

We could also verify this with more calculus of course.

Let's find the second derivative.

$f(x)=4x^3+13x^2-12x-56$