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Vedmedyk [2.9K]
3 years ago
7

Bjr j ai besoin d aide pour un devoir de math​

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
3 0
but j ai bessoin d aide pour devoir de leather ???
You might be interested in
Solve for y.<br> 4<br> -16 = -79<br> =<br> Simplify your answer as much as possible.
Verdich [7]

Answer:

The answer is -15.75 because 4= -16= -79 you have to turn 16 positive so add 16 to -79 to get -63 then divide by 4 to get the answer -15.75.

5 0
2 years ago
Help pls! Show your answers!
snow_tiger [21]

Answer:

The Asymptote would be at -3

Step-by-step explanation:

Just remember, when the number at the bottom (not the x) is positive, the graph would shift left by that number. And if it is negative, the graph would translate right by that number.

Since the function has positive 3, the asymptote is at -3

If the function was -3, the asymptote is at 3

EXTRA STUFF: If there is a number next to the fraction, that is not part of the denominator, then that is where the horizontal asymptote would be.

5 0
3 years ago
What is 7/2over 3 - 5/ 5 over 8
Lemur [1.5K]

Answer:

1.04166666667

3 0
4 years ago
Pls i need this today help me
kondaur [170]

Answer:

Step-by-step explanation:

a) 4x² + 20 = 0

          4x² = -20

            x² = -20/4

            x² = -5 = i² *5

             x = √i²5

            x = i√5

b) 4x² + 5 = -7

        4x² = -7 - 5

       4x² = - 12

          x² = -12/4

         x² = -3 = 3i²

        x = i√3

c) x² + 4x + 20 = 0

a = 1 ; b =4  ; c =20

x = \frac{-b+\sqrt{b^{2}-4ac}}{2a} and \frac{-b-\sqrt{b^{2}-4ac}}{2a};\\\\x = \frac{-4+\sqrt{16-4*1*20}}{2*1} and\frac{-4-\sqrt{16-4*1*20}}{2*1}\\\\=\frac{-4+\sqrt{16-80}}{2}  and \frac{-4-\sqrt{16+80}}{2}\\\\=\frac{-4+\sqrt{-64}}{2}    and  \frac{-4-\sqrt{64}}{2}\\\\= \frac{-4+8i}{2}  and\frac{-4-8}{2}

  = (-2 +4i)  & -12/2

  = (-2 + 4i) and (-6)  

5 0
3 years ago
If the volume of the pyramid shown is 360 inches cubed, what is its height?
dimaraw [331]

Answer:

9 inches

Step-by-step explanation:

The formula for the volume of a rectangular pyramid is V = \frac{1}{3}(l*w*h)

  • Here we have volume (V), base (L), and width (W)
  • V = 360 in³, L = 12 in, W = 10 in

We need to manipulate the volume equation to solve for the height (H)

  • First we need to multiply both sides by 3 to get rid of the fraction:  3V = L×W×H
  • Then we need to divide both sides by (L×W) to get: \frac{3V}{lw} =h

Now we can plug in the given values:

  • \frac{3(360in^{3}) }{(12 in)(10in)} =\frac{1080in^{3} }{120in^{2} } = 9in
  • The height is 9 inches
4 0
4 years ago
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