Bjr j ai besoin d aide pour un devoir de math

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

3 0

but j ai bessoin d aide pour devoir de leather ???

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(3x+2x^4)+(3x-5x^4)

natka813 [3]

Answer:

6x -3x^4

Step-by-step explanation:

Eliminate parentheses. Since the multiplying coefficient is +1, the parentheses can simply be dropped:

= 3x +2x^4 +3x -5x^4

Add like terms (ones with the same exponent on the variable).

= 3x +3x +2x^4 -5x^4 . . . . . . . group like terms together

= (3+3)x +(2-5)x^4

= 6x -3x^4

7 0

4 years ago

F(x)=(x – 5)(x+3)(x-1)<br> Degree?

marshall27 [118]

Answer:

3rd degree 3 is the highest power

Step-by-step explanation:

7 0

3 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

Rudik [331]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$