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3 years ago

9

to determine whether a number is written in scientific notation what test can you apply to the first factor and what test can yo

u apply to the second factor

1 answer:

pashok25 [27]3 years ago

6 0

Answer:

Step-by-step explanation:

The first term must have one number before decimal point

the second term (factor) must be 10 having some power.

example;

5.0 ×10³

7.002×10^41

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IfA=(-2,-4) and B=(-8,4), what is the length of AB?

lisabon 2012 [21]

Answer:

<h2>10 units </h2>

solution,

A(-2,-4)--->(X1,y1)

B(-8,4)----->(x2,y2)

now,

$ab = \sqrt{(x2 - x1) ^{2} + {(y2 - y1)}^{2} } \\ \: \: \: \: = \sqrt{ (- 8 - ( - 2)) ^{2} + (4 - ( - 4)) ^{2} } \\ \: \: \: = \sqrt{( - 8 + 2) ^{2} + {(4 + 4)}^{2} } \\ \: \: \: = \sqrt{( - 6) ^{2} + {(8)}^{2} } \\ \: \: = \sqrt{36 + 64} \\ \: \: \: = \sqrt{100} \\ \: \: \: = \sqrt{ {(10)}^{2} } \\ \: \: \: \: = 10 \: units$

Hope this helps..

Good luck on your assignment

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3 years ago

Mom has 4 red buttons dad has three blue buttons and and baby has green buttons. How many buttons doed the famiky have

Vladimir [108]

The answer will depend how many buttons does the baby have. You just have to add all the buttons together, and that will be your answer.

So 4+3+green buttons =the answer

8 0

2 years ago

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3 years ago

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Find the solutions to the system; y=x^2-3x-1 and y=8x-1

PSYCHO15rus [73]

${x}^{2} - 3x - 1 = 8x - 1 \\ {x}^{2} - 11x = 0 \\ x(x - 11) \\ x = 0 \: or \: x = 11$

When x = 0,
$y = 8x - 1 \\ y = 0 - 1 \\ y = - 1$

When x = 11
$y = 8(11) - 1 \\ y = 87$
x = 0, y = - 1
x = 11, y = 87

Answer is B.

Hope this helps. - M

8 0

3 years ago

Determine whether or not the relation is a function. Please help asap

OLga [1]

Answer:

A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function

Step-by-step explanation:

4 0

2 years ago