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svet-max [94.6K]
3 years ago
6

Help please ASAP!!!! I NEED CORRECT ANSWERS ONLY FOR BRAINLIEST

Mathematics
1 answer:
MrRissso [65]3 years ago
5 0

Let us start subtracting 3 cos theta both sides so that we may get all theta terms on left side only

It is now : 4 cos theta - 3 cos theta = - (sqrt3)/ 2

1 cos theta = -( sqrt 3 ) /2

we know cos (pi-x)= - cos x And cos (pi+ x)= - cos (x)

********* let us first use :

- Cos ( pi - theta) = - ( sqrt 3 )/2

this implies cos (pi- theta )= (sqrt 3) /2

cos ( pi - theta )= cos (pi /6)

pi- theta = pi/6

pi- pi/6 = theta

5 pi/6 = theta

one of teh answer is 5 pi/6 . another value of theta would be :

(2pi - 5pi/6)= 7pi/6

Answer: 5 pi/6 and 7 pi/6

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This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

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Dime = $0.10

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q=\frac{1}{2} d

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Simplify the expression.

9d + 2n = 440

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Multiply both sides of the equation by -9.

-9d + 9n = 108

9d + 2n = 440

Sum the equations vertically to eliminate at least one variable.

11n = 548

n=\frac{548}{11}

Substitute the given value of n into the equation d - n = -12

d-\frac{548}{11} =-12

d=\frac{416}{11}

Substitute the given value of n into the equation q=\frac{1}{2} d

q=\frac{1}{2} *\frac{416}{11}

q=\frac{208}{11}

Finally

d=\frac{416}{11}        d = 37.818

n=\frac{548}{11}        n = 49.818

q=\frac{208}{11}        q = 18.909

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