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lidiya [134]
4 years ago
6

Write the equation of the parabola whose focus is (4,0) and directrix at y = 2

Mathematics
1 answer:
goldfiish [28.3K]4 years ago
3 0

Answer:

\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}=\left ( y-2 \right )^{2}

Step-by-step explanation: We know that distance from a point on the parabola and  focus is equal to their distance from a the directrix. Let (x, y) be the point,

So,

\sqrt{\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}}=\frac{\left | y-2 \right |}{1}

\left ( x-4 \right )^{2}+\left ( y-0 \right )^{2}=\left ( y-2 \right )^{2}. This is the required equation.

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Step-by-step explanation:

The expression for the function f(x) would be represented in the slope-intercept form, y = mx + c

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Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

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The line passes through (8, - 5) and (- 9, 2),

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The equation becomes

f(x) = - 7x/17 - 29/17

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