Answer:
The standard error of the mean is 4.5.
Step-by-step explanation:
As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.
The mean of the sample is:

The standard deviation of the sample is calculated as:

Then, we can calculate the standard error of the mean as:

For this problem, I'd use cross-multiplication.
9/12 = x/8.
When cross multiplying, multiply 12*x and 9*8. This leads to a new equation:
12x = 72.
Then you solve as an algebra problem.
*Divide 12 on both sides*
x = 6.
The total amount the Noah receives will be equal to his hourly payment multiplied by the number of working of hours added to the 500$ bonus which he received.
Now, Noah get 28$ per hour and he works for x hours. This means that the payment he gets for working = 28x
Then, we will add the $500 which he received as a bonus.
Doing this, we can get the expression that models his total payment as follows:
y = 28x + 500