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Svetradugi [14.3K]
2 years ago
8

Round 639,121 to the nearest ten thousand.

Mathematics
2 answers:
denpristay [2]2 years ago
7 0

Answer:

640,000

Step-by-step explanation:

or 640,121

VLD [36.1K]2 years ago
4 0

Answer:

640,121

Step-by-step explanation:

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How to find standard deviation from percentile for normal distribution?
QveST [7]
The standard deviation of what?  Percentiles from any normal distribution look the same, just like the unit normal, so you can't really determine the standard deviation of the original scores. You can determine a z score from a percentile.  That tells us the number of standard deviations, positive or negative, a given score is away from the mean score.  It's a normalized test result.

Your percentile is (a hundred times) the probability that another score is less than your score.  We have a normal distribution, so that probability is the integral of the standard normal from negative infinity to our normalized score.  

Let's call the percentile rank p, already scaled between zero and 1.

p=.5 corresponds to a z score z=0 because the fiftieth percentile means we got an exactly average score, 0 standard deviations away from the mean.

We know 68% of the probability will be between -1 and +1 standard deviation.  So z=-1 corresponds to p=.5-.68/2=.16 and
z=1 corresponds to p=.5+.68/2=.84

Similarly, 95% of the probability will be between -2 and +2 standard deviations.  So z=-2 corresponds to p=.5-.95/2=.025 and
z=2 corresponds to p=.5+.95/2=.975

That's about the list I can do off the top of my head. I think three standard deviations is 99.7%. For the rest we just consult a z table or integrated normal table.  We find p in the body of the table (maybe |.5-p| depending on the table) and then the column headings tell us our z score.

In this modern age, your computer can do this for you quickly

8 0
3 years ago
Fred got a score of 68 on the test. Enter a division sentence using negative numbers where the quotient represents the number of
Contact [7]
100 / 68 equals negative 32.
4 0
3 years ago
Read 2 more answers
Trigonometric Identities
bogdanovich [222]
\bf \textit{symmetry identities}\\\\
sin(-\theta )\implies -sin(\theta )\qquad \qquad cos(-\theta )\implies cos(\theta )
\\\\\\also~recall\\\\ sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
sin^2(\theta)=1-cos^2(\theta)
\\\\
-------------------------------\\\\\
[1-cos(-t)][1+cos(t)]\implies [1-cos(t)][1+cos(t)]

\bf 1^2-cos^2(t)\implies 1-cos^2(t)\implies sin^2(t)\\\\
-------------------------------\\\\\
%Simplify each expression.  (1−cos⁡(−t))(1+cos⁡(t)) =  (1+sin(t))(1+sin(-t))=  csc⁡(t)tan⁡(t)+sec⁡(−t) =
[1+sin(t)][1+sin(-t)]\implies [1+sin(t)][1-sin(t)]
\\\\\\
1^2-sin^2(t)\implies 1-sin^2(t)\implies cos^2(t)\\\\
-------------------------------\\\\

\bf csc(t)tan(t)+sec(-t)\implies \cfrac{1}{\underline{sin(t)}}\cdot \cfrac{\underline{sin(t)}}{cos(t)}+\cfrac{1}{cos(-t)}
\\\\\\
\cfrac{1}{cos(t)}+\cfrac{1}{cos(-t)}\implies \cfrac{1}{cos(t)}+\cfrac{1}{cos(t)}\implies \cfrac{2}{cos(t)}
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2\cdot \cfrac{1}{cos(t)}\implies 2sec(t)
3 0
3 years ago
How do you find this?
Molodets [167]

Answer:

b

Step-by-step explanation:

4 0
3 years ago
The value -2 is a lower bound for the zeros of the function shown below.
Juliette [100K]

Answer:

  a) true

Step-by-step explanation:

The bottom-line numbers from synthetic division <em>alternate signs</em>, indicating that -2 is a lower bound. The given statement is true.

__

If the signs were all positive, it would indicate the proposed zero is an <em>upper bound</em>.

__

A graph shows all real zeros are greater than -2.

4 0
3 years ago
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