<h3>The required value of
![\lim_{h \to0 \zero} 46x^11+32xh^3+6x^15h+23](https://tex.z-dn.net/?f=%5Clim_%7Bh%20%5Cto0%20%5Czero%7D%2046x%5E11%2B32xh%5E3%2B6x%5E15h%2B23)
is
![46x^11+23](https://tex.z-dn.net/?f=46x%5E11%2B23)
What is limit?</h3>
Limit, can be defined as the every nearby the value of a variable for a function exists, is called limits|
⇒ ![\lim_{h \to0 \zero} 46x^11+32xh^3+6x^15h+23](https://tex.z-dn.net/?f=%5Clim_%7Bh%20%5Cto0%20%5Czero%7D%2046x%5E11%2B32xh%5E3%2B6x%5E15h%2B23)
When putting h = 0
⇒ ![46x^11+23](https://tex.z-dn.net/?f=46x%5E11%2B23)
Thus, the value of a function of its limit is given by ![46x^11+23](https://tex.z-dn.net/?f=46x%5E11%2B23)
Learn more about limits here:
brainly.com/question/18008819
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![BA = BC = 12](https://tex.z-dn.net/?f=BA%20%3D%20BC%20%3D%2012)
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![AC = BA + BC](https://tex.z-dn.net/?f=AC%20%3D%20BA%20%2B%20BC)
![AC = 12 + 12](https://tex.z-dn.net/?f=AC%20%3D%2012%20%2B%2012)
![AC = 24](https://tex.z-dn.net/?f=AC%20%3D%2024)
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Answer:
36.
Step-by-step explanation:
We are asked to find the number of ways in which 3 girls can divide 10 pennies such that each must end up with at least one penny.
The selection can be done by selecting two dividing likes between the 10 pennies such that the set is divided into three parts.
Since each girl must have one penny, so no girl can have 0 penny. So the dividing like cannot be placed at end points, beginning and at the end. Therefore, we are left with 9 positions.
Now we need to find number of ways to select two positions out of the 9 positions that is C(9,2).
![_{2}^{9}\textrm{C}=\frac{9!}{7!*2!}=\frac{9*8*7!}{7!*2*1}=\frac{9*8}{2}=9*4=36](https://tex.z-dn.net/?f=_%7B2%7D%5E%7B9%7D%5Ctextrm%7BC%7D%3D%5Cfrac%7B9%21%7D%7B7%21%2A2%21%7D%3D%5Cfrac%7B9%2A8%2A7%21%7D%7B7%21%2A2%2A1%7D%3D%5Cfrac%7B9%2A8%7D%7B2%7D%3D9%2A4%3D36)
Therefore, there are 36 ways to divide 10 pennies between 3 girls.
Parallelogram so
CD = AB
18x - 5 = 15x + 4
3x = 9
x = 3
answer
x = 3
Answer:
The probability is 0
Step-by-step explanation:
Since proportion of time spent on mowing will be 200/400 = 0.5, there will be no chance that the true proportion of time spent mowing is exactly equal to the sample proportion. Where true proportion is 200 and sample is 400 . So the probability is 0.