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disa [49]
3 years ago
14

I need to know how to write a equation number sentence for my time traveled from 2020 to 2000

Mathematics
1 answer:
vesna_86 [32]3 years ago
5 0

Answer:

explain further or send a picture of what you mean and then I can help you

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If ten coins are spun together, the probability of four or more heads is 0.83. the probability of eight or more is 0.05. find th
aleksklad [387]

Answer:

a. 0.17

b. 0.95

Step-by-step explanation:

The key to answering both questions is that we should understand that the probability of an event happening = 1 - the probability of the event not happening

Firstly, we want to calculate the probability of less than four

Probability of less than four = 1 - probability of four or more heads

that is 1 - 0.83 = 0.17

Probability of less than 8 = 1 - probability of 8 or more = 1-0.05 = 0.95

6 0
3 years ago
Convert the fractions to decimals using long division 4/7
stealth61 [152]

Answer:

0.57142857142

Step-by-step explanation:

it goes on and on tho

3 0
3 years ago
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??? Help me with my work pls
serious [3.7K]

Answer:

2. 10 + 5 x 2                    $20

3. 10 + 5 x 3                    $25

4. 10 + 5 x 4                    $30

Hope that helps!

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The pair of variables x=5, y=7 is the solution to the equation ax–2y=1. Find the coefficient a.
Wewaii [24]

Answer:

a=3

Step-by-step explanation:

This should be very simple, just substitute xy and y for 5 and 7 respectively, so 5a-2*7=1, or 5a-14=1, or 5a=15, if we divide both sides by 5, we get a=3

5 0
3 years ago
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Prove that sin^2A/cos^2A + cos^2A/sin^2A = 1/cos^2A*sin^2A - 2
jenyasd209 [6]

Answer:

prove that:

Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2

LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}

Cos

2

A

Sin

2

A

+

Sin

2

A

Cos

2

A

= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}

=

Cos

2

A.Sin

2

A

Sin

4

A+Cos

4

A

Usinga

2

+b

2

=(a+b)

2

−2ab

a=Cos

2

A&b=Sin

2

A

=

Cos

2

ASin

2

A

(Sin

2

A+Cos

2

A)

2

−2Sin

2

ACos

2

A

Sin

2

A+Cos

2

A=1

=

Cos

2

ASin

2

A

1−2Sin

2

ACos

2

A

\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}

=

Cos

2

ASin

2

A

1

−2

=RHS

LHS=RHS

4 0
3 years ago
Read 2 more answers
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