Question

Find the 12th term of the geometric sequence

Answer 1

The 12th term of the geometric sequence would be -8,388,608.

Step-by-step explanation:

Given that,

The first term of geometric sequence is = a1 = 2

a2 = -8

a3 = 32

Now, the formula for nth term of a geometric sequence is $an = a*r^{n-1}$

So,

$a1 = a*r^{1-1} = a*rx^{0} = a*1 = a$

$a2 = a*r^{2-1} = a*rx^{1} = a*r$

Now,

a = 2

a*r = -8

By putting the value of a, we get

2*r = -8

or

r = -4

For 12th term, the formula would be:

$a1 2 = a*r^{12-1} = a*r^{11}$

now, put the values of a and r:

$a12 = 2*(-4)^{11}$

a12 = 2 * (-4,194,304)

a12 = -8,388,608

Hence, the 12th term of the geometric sequence would be -8,388,608.