Answer:
is there an image provided?
Step-by-step explanation:
Answer:
c≥2(x-2) ÷ 5
Step-by-step explanation:
5c+3≥6x-8
5c ≥6x-8-3
5c≥6x-12
c≥(6x-12) ÷ 5
c≥ 2(x-2) ÷5
as the following pic you can see the answer.
#diameter is 8 so radius is 4
Answer:
hey:)
the answer is -8.11
there is no step-by-step explanation, because you have to either do it with a calculator or do it by yourself
Answer:
![2(x-1)^{2}=4](https://tex.z-dn.net/?f=2%28x-1%29%5E%7B2%7D%3D4)
Step-by-step explanation:
<u><em>The options of the question are</em></u>
2(x − 1)2 = 4
2(x − 1)2 = −4
2(x − 2)2 = 4
2(x − 2)2 = −4
we have
![2x^{2} -4x-2=0](https://tex.z-dn.net/?f=2x%5E%7B2%7D%20-4x-2%3D0)
This is a vertical parabola open upward
The vertex represent the minimum value
The quadratic equation in vertex form is
![y=a(x-h)^2+k](https://tex.z-dn.net/?f=y%3Da%28x-h%29%5E2%2Bk)
where
a is a coefficient
(h,k) is the vertex
so
Convert the quadratic equation in vertex form
Factor 2 leading coefficient
![2(x^{2} -2x)-2=0](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D%20-2x%29-2%3D0)
Complete the squares
![2(x^{2} -2x+1)-2-2=0](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D%20-2x%2B1%29-2-2%3D0)
![2(x^{2} -2x+1)-4=0](https://tex.z-dn.net/?f=2%28x%5E%7B2%7D%20-2x%2B1%29-4%3D0)
Rewrite as perfect squares
![2(x-1)^{2}-4=0](https://tex.z-dn.net/?f=2%28x-1%29%5E%7B2%7D-4%3D0)
The vertex is the point (1,-4)
Move the constant to the right side
![2(x-1)^{2}=4](https://tex.z-dn.net/?f=2%28x-1%29%5E%7B2%7D%3D4)