All categories

3 years ago

Which measures are $1 greater for Group B than for Group A?

Mathematics

2 answers:

mart [117]3 years ago

8 0

Answer:

the right answer is c. mean and the median

Step-by-step explanation:

because i took the test and got the answer right

jekas [21]3 years ago

7 0

Answer:

it is the mode and range

You might be interested in

Employee I has a higher productivity rating than employee II and a measure of the total productivity of the pair of employees is

Schach [20]

Answer:

The variance of the measure of productivity = 141.67(to 2 d.p)

Step-by-step explanation:

The complete question and the step-by step explanation are contained in the files attached to this solution.

8 0

3 years ago

What is the slope intercept form of -11x+2y=1?

ikadub [295]

Answer:

y= 11/2 x+1/2

Step-by-step explanation:

Slope Intercept form: y = mx + b where m = slope of the line, b = y intercept and (x,y) are coordinate points on the line.

To put this in slope-intercept form, you need to solve the equation for y

-11x + 2y = 1

+11x +11x add 11x to both sides of the equation

+2y = 1 + 11x

2 2 Divide both sides by 2 (so y is by itself)

y = 11/2x + 1/2

6 0

3 years ago

6. What is the distance between -3 and 2 on the number line?

icang [17]

Answer:

5 jumps to the right

<h2>hope it helps :D</h2>

7 0

3 years ago

Find the missing side lengths. Leave your answers as radicals in simplest form. Please help!! Due today

Nataly_w [17]

Answer:

$m = 10\sqrt 3$

$n = 10$

Step-by-step explanation:

Required

Find m and n

Considering the given angle, we have:

$\sin(60) = \frac{Opposite}{Hypotenuse}$

This gives:

$\sin(60) = \frac{m}{20}$

Make m ths subject

$m = 20 * \sin(60)$

$\sin(60) =\frac{\sqrt 3}{2}$

So, we have:

$m = 20 *\frac{\sqrt 3}{2}$

$m = 10\sqrt 3$

Considering the given angle again, we have:

$\cos(60) = \frac{Adjacent}{Hypotenuse}$

This gives:

$\cos(60) = \frac{n}{20}$

Make n the subject

$n = 20 * \cos(60)$

$\sin(60) =\frac{1}{2}$

So, we have:

$n = 20 *\frac{1}{2}$

$n = 10$

5 0

3 years ago

Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) . Write the coordinate notation for a translation of 8 units right

Dovator [93]

Triangle JKL has vertices J(−2, 2) , K(−3, −4) , and L(1, −2) .

Rule: (x, y)→(x + 8, y + 1 )

J’ (-2, 2) → (-2 + 8, 2 + 1 ) → (6, 3 )
K’ (-3, -4) → (-3 + 8, -4 + 1 ) → (5, -3 )
L’ (1, -2) → (1 + 8, -2 + 1 ) → (9, -1)

J’ (6,3)
K’ (5,-3)
L’ (9,-1)

Hope this helps!

3 0

2 years ago