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ch4aika [34]
1 year ago
14

A jewelry store has 212.75 ounces of 14-carat gold in stock. (a) how many custom necklaces can be manufactured if each requires

2 7/8 ounces of gold? (b) if gold is currently selling for $1,050 per ounce, how much is the gold in each necklace worth (in $)?
Mathematics
2 answers:
Nonamiya [84]1 year ago
6 0

Answer:

a. The number of custom necklaces that can be manufactured if each requires 2 7/8 ounces of gold is 74 necklaces.

b. The value of the gold in each necklace is $1761

Step-by-step explanation:

(a) Number of necklaces

27/8 ounces of gold=2.875

No of necklaces=212.75oz x 1 necklaces/2.875oz

                          =74 necklaces

(b)Value of gold in each necklace

There are 2.875 oz of 14K gold in each necklace. Pure gold is 24K.

Mass of pure gold=2.875oz x 14k/24k

                              =1.677083oz

Pure 24K gold is worth $1050/oz.

Value of pure gold=1.677oz x 1050/1oz

                              = 1760.9 dollars

The value of the gold in each necklace is $1761

#SPJ4

Learn more on

brainly.com/question/12983156

Anna007 [38]1 year ago
3 0

a) Number of custom necklaces that can be crafted if each requires 2 7/8 ounces of gold which is 74 necklaces.

b) The gold value of each necklace is $1761

  • Algebra is a branch of mathematics that deals with symbols and the rules for using those symbols.  

  • In elementary algebra, these symbols (now written in Latin and Greek letters) represent quantities with no fixed value, called variables.  

(a) Number of necklaces

2 7/8 ounces of gold = 2.875

Number of necklaces = 212.75 oz x 1 necklace / 2,875 oz

= 74 necklaces

(b) Gold value in each necklace

There is 2,875 oz of 14k gold in each necklace. Pure gold is 24K.

Mass of pure gold = 2,875 oz x 14k / 24k

= 1.677083oz

Pure 24-karat gold is worth $1,050 per ounce.

Pure Gold Value = 1,677 oz x 1050/1 oz

= $1760.9

The gold value of each necklace is $1761

Learn more about algebra here

https://brainly.in/question/26500

#SPJ4

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Step-by-step explanation:

<em><u>Given</u></em><em><u>, </u></em>

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Area of the parallelogram = <em>base</em><em> </em><em>×</em><em> </em><em>height</em><em> </em>

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<em><u>Hence</u></em><em><u>,</u></em>

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Using the speed - distance relationship, the time left before the appointed time is 27 minutes.

<u>Recall</u><u> </u><u>:</u>

  • Distance = speed × time

  • Let time = t

<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>

  • Distance = 10 × (t + 3) = 10t + 30 - - - (1)

<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>

  • Distance = 12 × (t - 2) = 12t - 24 - - - - (2)

<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>

10t + 30 = 12t - 24

<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>

10t - 12t = - 24 - 30

-2t = - 54

<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>

t = 54 / 2

t = 27

Hence, the time left before the appointed time is 27 minutes.

Learn more : brainly.com/question/25669152

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