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3 years ago

Had to repost 4 times because no one's been able to do it.

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

Answer:

I think A

Step-by-step explanation:

I am not quite sure what this is asking, but based off of what I can tell it should be A.

Hope this helps :)

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F(x) = √3x

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The domain of the function is $(\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2}$ . $x \ne -\frac 25$

<h3>How to determine the domain and the restrictions?</h3>

The attached image represents the complete form of the question

The functions are given as:

$f(x) = \sqrt[3]{3x}$

g(x) = 5x + 2

The function (f/g)(x) is calculated using:

$(\frac{f}{g})(x) = \frac{f(x)}{g(x)}$

This gives

$(\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2}$

The denominator cannot be 0.

So, we have:

$5x + 2 \ne 0$

Solve for x

$x \ne -\frac 25$

Hence, the domain of the function is $(\frac{f}{g})(x) = \frac{\sqrt[3]{3x}}{5x + 2}$ . $x \ne -\frac 25$