Evaluate the expression 6h ÷ 2 when h = 3
2 answers:
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Answer:
The polynomial is a quadratic binomial
Step-by-step explanation:
we have
Classify the polynomial
<u>By the number of terms</u>
we know that
A polynomial with two terms is a binomial
<u>By the Degree of a Polynomial</u>
we know that
The degree of a polynomial is calculated by finding the largest exponent in the polynomial
In the given problem the largest exponent is
so
Is a quadratic equation
therefore
The polynomial is a quadratic binomial
Answer:
Part 1) Is a inconsistent system
Part 2) Is a consistent independent system
Part 3) Is a consistent dependent system
see the attached figure
Step-by-step explanation:
we know that
If a system has at least one solution, it is said to be consistent .
If a consistent system has exactly one solution, it is independent .
If a consistent system has an infinite number of solutions, it is dependent
If a system not have solution, it is said to be inconsistent
Part 1) we have
This system of linear equations has two parallel lines (their slopes are equal) with different y-intercept
so
The lines don't intersect
The system has no solution
therefore
Is a inconsistent system
Part 2) we have
we know that
If two lines have different slopes, then the lines intersect at one point and the system of equations has one solution
In this problem, the lines have different slopes (m=3 and m=2)
so
The lines intersect at one point
The system has one solution
therefore
Is a consistent independent system
Part 3) we have
----> equation A
----> equation B
Multiply equation A by -2 both sides
----> equation C
Compare equation B and equation C
Are identical lines
so
The system has infinity solutions
therefore
Is a consistent dependent system
Given:
The rate of interest on three accounts are 7%, 8%, 9%.
She has twice as much money invested at 8% as she does in 7%.
She has three times as much at 9% as she has at 7%.
Total interest for the year is $150.
To find:
Amount invested on each rate.
Solution:
Suppose x be the amount invested at 7%. Then,
The amount invested at 8% = 2x
The amount invested at 9% = 3x
Total interest for the year is $150.
Multiplying both sides by 100, we get
Dividing both sides by 50, we get
So, the amount invested at 7% is .
The amount invested at 8% is
The amount invested at 9% is
Hence, the stockbroker invested $300 at 7%, $600 at 8%, and $900 at 9%.